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Jlenok [28]
3 years ago
9

Plz help me answer this question

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
8 0
A. 5 invitations
b. 15 invitations
Comment if you need me to explain it.

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Inverse function y = x2 − 18x.
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Is 4/5 equal to 8/9? Explain please! PS I just put in a random fraction I did not know if it was equal or not.
natita [175]
8/10 because equal fractions have to be multiplied by 2
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Question
Mademuasel [1]

Answer:

<u>The cost to rent a rug cleaner for 6 days is $ 58</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Cost to rent a rug cleaner for d days = 5.50d + 25

2. Find the cost to rent the cleaner for 6 days.

Cost to rent a rug cleaner for 6 days = 5.50 * 6 + 25

Cost to rent a rug cleaner for 6 days = 33 + 25

Cost to rent a rug cleaner for 6 days = $ 58

<u>The cost to rent a rug cleaner for 6 days is $ 58</u>

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3 years ago
What is x? 15(x-1)-7(x+9)=4x
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7 0
3 years ago
The curved surface area of a right circular cylinder of height 14 cm is 88 cm². ​
Slav-nsk [51]

Answer:

The diameter of the base of the cylinder is 2 cm.

Step-by-step explanation:

<u>GIVEN</u> :

As per given question we have provided that :

  • ➣ Height of cylinder = 14 cm
  • ➣ Curved surface area = 88 cm²

\begin{gathered}\end{gathered}

<u>TO</u><u> </u><u>FIND</u> :

in the provided question we need to find :

  • ➠ Radius of cylinder
  • ➠ Diameter of cylinder

\begin{gathered}\end{gathered}

<u>USING</u><u> </u><u>FORMULAS</u> :

\star{\underline{\boxed{\sf{\purple{Csa = 2 \pi rh}}}}}

\star{\underline{\boxed{\sf{\purple{d = 2r}}}}}

  • ➛ Csa = Curved surface area
  • ➛ π = 22/7
  • ➛ r = radius
  • ➛ h = height
  • ➛ d = diameter

\begin{gathered}\end{gathered}

<u>SOLUTION</u> :

Firstly, finding the radius of cylinder by substituting the values in the formula :

\begin{gathered} \qquad{\longrightarrow{\sf{Csa = 2 \pi rh}}} \\  \\ \qquad{\longrightarrow{\sf{88 = 2 \times \dfrac{22}{7} \times r \times 14}}}  \\  \\ \qquad{\longrightarrow{\sf{88 =\dfrac{44}{7} \times r \times 14}}} \\  \\ \qquad{\longrightarrow{\sf{88 =\dfrac{44}{\cancel{7}}\times r \times  \cancel{ 14}}}}  \\  \\  \qquad{\longrightarrow{\sf{88 =44 \times r \times 2}}} \\  \\ \qquad{\longrightarrow{\sf{88 =88 \times r}}} \\  \\ \qquad{\longrightarrow{\sf{r =  \frac{88}{88}}}} \\  \\ \qquad{\longrightarrow{\underline{\underline{\sf{\pink{r = 1 \: cm}}}}}} \end{gathered}

Hence, the radius of cylinder is 1 cm.

———————————————————————

Now, finding the diameter of cylinder by substituting the values in the formula :

\begin{gathered} \qquad{\longrightarrow{\sf{d = 2r}}} \\  \\  \qquad{\longrightarrow{\sf{d = 2 \times 1}}} \\  \\ \qquad{\longrightarrow{\underline{\underline{\sf{\red{r = 2 \: cm}}}}}}\end{gathered}

Hence, the diameter of the base of the cylinder is 2 cm.

\rule{300}{2.5}

3 0
2 years ago
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