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Flura [38]
3 years ago
14

Quadrilateral ABCD is reflected across the x-axis and then reflect across the y-axis to form quadrilateral A′B′C′D′. If the coor

dinates of vertex A are (-7, 3), what are the coordinates of vertex A′?
A.
(7, 3)
B.
(-7, -3)
C.
(7, -3)
D.
(-7, 3)
E.
(3, 7)
int not b im on plato edmetum
Mathematics
1 answer:
marissa [1.9K]3 years ago
5 0

Answer:

D (-7,3)

Step-by-step explanation:

When we reflect across the x-axis, we negate the y-axis.

This means that; (x,y)\to(x,-y)

If the coordinates of vertex A are (-7, 3), then after a reflection in the x-axis, we obtain:

(-7,3)\to(-7,-3)

For a reflection in the y-axis, we negate the x-coordinate to get;

(-7,-3)\to(--7,-3) =(7,-3)

Therefore the coordinate of A' are (7,-3)

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Answer:

<em>Observe attached image</em>

<em>Function zeros:</em>

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<em>Vertex:</em>

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<em>Axis of symmetry:</em>

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Step-by-step explanation:

<u>First factorize the function</u>

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<em>Now factor the expression x ^ 2 -8x +15</em>

You must find two numbers that when you add them, obtain the result -8 and multiplying those numbers results in 15.

These numbers are -5 and -3

Then we can factor the expression in the following way:

f (x) = -2(x-5)(x-3)

<em><u>The quadratic function cuts the x-axis at </u></em><em>x = 3 and at x = 5.</em>

Now we find the coordinates of the vertex.

For a function of the form ax ^ 2 + bx + c the x coordinate of its vertex is:

x = \frac{-b}{2a}

In the function f (x) = -2x ^ 2 + 16x-30

a = -2\\b = 16\\c = 30

<u>Then the vertice is:</u>

x = \frac{-16}{2(-2)}\\\\x = 4

The y coordinate of the symmetry axis is

y = f (4) = -2 (4) ^ 2 +16 (4) -30\\\\y = 2

The axis of symmetry is a vertical line that cuts the parabola in two equal halves. This axis of symmetry always passes through the vertex.

<u>Then the axis of symmetry is the line</u>

x = 4

<u>The solutions and the vertice written as ordered pairs are:</u>

<em>Function zeros:</em>

(3, 0), (5, 0)

<em>Vertex:</em>

(4, 2)

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