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antiseptic1488 [7]
3 years ago
10

Please help click on the image below

Mathematics
1 answer:
AveGali [126]3 years ago
8 0
If you look at how x and y compare, x is multiplied by 2.11 to get Y. The answer is the third one, y=2.11x
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Part ion even know of the hardest test
ladessa [460]

Given:

The equation of a line is:

y=-\dfrac{5}{7}x+2

A line passes through the point (-5,-3) and perpendicular to the given line.

To find:

The equation of the line.

Solution:

Slope intercept form of a line is:

y=mx+b                 ...(i)

Where, m is the slope and b is the y-intercept.

We have,

y=-\dfrac{5}{7}x+2          ...(ii)

On comparing (i) and (ii), we get

m=-\dfrac{5}{7}

We know that the product of slopes of two perpendicular lines is always -1.

m_1\times m_2=-1

-\dfrac{5}{7}\times m_2=-1

m_2=\dfrac{7}{5}

Slope of the required line is \dfrac{7}{5} and it passes through the point (-5,-3). So, the equation of the line is:

y-y_1=m_2(x-x_1)

y-(-3)=\dfrac{7}{5}(x-(-5))

y+3=\dfrac{7}{5}(x+5)

Using distributive property, we get

y+3=\dfrac{7}{5}(x)+\dfrac{7}{5}(5)

y+3=\dfrac{7}{5}x+7

y=\dfrac{7}{5}x+7-3

y=\dfrac{7}{5}x+4

Therefore, the equation of the line is y=\dfrac{7}{5}x+4. Hence, option A is correct.

4 0
3 years ago
Solve the following equation: 7x - 8 = 3x + 12
Paul [167]
X=5
7(5)-8=35-8=27
3(5)+12=15+12=27
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2 years ago
Find the point in the first octant where the tangent plane to x2+116y2+14z2=1 is parallel to the plane x+y+z=10
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2x+3=yx bc it makes the most sence
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A stone is thrown upward from ground level. With what minimum speed should the stone be thrown so as to reach a height of 81 fee
butalik [34]
Use the kinematics equation:
v1^2-v0^2=2as
since v1=0 (at height of 81 ft), and a=g=-32.2, substitute values:

0-v0^2=2*(-32.2)(81 ft)
Solve for v0
v0=sqrt(2*32.2*81)=72.2 m/s
3 0
3 years ago
Read 2 more answers
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