Yo sup??
First measurement=44 mm
Second measurement=7.6 cm
=7.6*10 mm
=76 mm
Ratio=76:44
=19:11
Hope this helps
To solve using completing square method we proceed as follows:
x^2-10x+8=0
x^2-10x=-8
but
c=(b/2)^2
c=(10/2)^2=25
thus we can add this in our expression to get
x^2-10x+25=8+25
factorizing the LHS we get:
(x-5)(x-5)=33
(x-5)^2=33
getting the square roots of both sides we have:
x-5=+/-√33
x=5+/-√33
Answer:
yes
Step-by-step explanation:
The equation of a horizontal line parallel to the x-axis is
y = c
where c is the value of the y- coordinates the line passes through
y = 4 is a horizontal line passing through all points with a y- coordinate of 4
Answer:
y -6 = 1/3(x +3) or y = 1/3x +7
Step-by-step explanation:
The slope of the line describing the given path is the x-coefficient, -3. The slope of the perpendicular line will be the negative reciprocal of that:
m = -1/(-3) = 1/3
The point-slope form of the equation for a line can be used to write the equation for the new path:
y -k = m(x -h) . . . . . line with slope m through point (h, k)
For m=1/3 and (h, k) = (-3, 6), the new path can be represented by ...
y -6 = 1/3(x +3) . . . . point-slope form
y = (1/3)x +7 . . . . . . slope-intercept form
(d) The particle moves in the positive direction when its velocity has a positive sign. You know the particle is at rest when
and
, and because the velocity function is continuous, you need only check the sign of
for values on the intervals (0, 3) and (3, 6).
We have, for instance
and
, which means the particle is moving the positive direction for
, or the interval (3, 6).
(e) The total distance traveled is obtained by integrating the absolute value of the velocity function over the given interval:

which follows from the definition of absolute value. In particular, if
is negative, then
.
The total distance traveled is then 4 ft.
(g) Acceleration is the rate of change of velocity, so
is the derivative of
:

Compute the acceleration at
seconds:

(In case you need to know, for part (i), the particle is speeding up when the acceleration is positive. So this is done the same way as part (d).)