Answer: Original expression: 2x - 11 + 4x + 7 + 3(x-4)
Simplified: 9x - 16
Step-by-step explanation:
2x - 11 + 4x + 7 + 3(x-4) becomes 2x - 11 + 4x + 7 + 3x -12
Group like terms, then combine to simplify:
2x + 4x + 3x -11 + 7 - 12
2x + 4x + 3x = 9x
-11 -12 + 7 = =23+7= -16
Simplified expression: 9x - 16
The initial investment = $250
<span>annual simple interest rate of 3% = 0.03
</span>
Let the number of years = n
the annual increase = 0.03 * 250
At the beginning of year 1 ⇒ n = 1 ⇒⇒⇒ A(1) = 250 + 0 * 250 * 0.03 = 250
At the beginning of year 2 ⇒ n = 2 ⇒⇒⇒ A(2) = 250 + 1 * 250 * 0.03
At the beginning of year 3 ⇒ n = 3 ⇒⇒⇒ A(2) = 250 + 2 * 250 * 0.03
and so on .......
∴ <span>The formula that can be used to find the account’s balance at the beginning of year n is:
</span>
A(n) = 250 + (n-1)(0.03 • 250)
<span>At the beginning of year 14 ⇒ n = 14 ⇒ substitute with n at A(n)</span>
∴ A(14) = 250 + (14-1)(0.03*250) = 347.5
So, the correct option is <span>D.A(n) = 250 + (n – 1)(0.03 • 250); $347.50
</span>
Answer:
3/2
Step-by-step explanation:
y2 - y1/ x2 - x1
7 -(-5) / 6 - (-2)
12/ 8
3/2
