Answer:
(a)5 and 8
(b)5 and 5
(c) 7 and 5
(d)6 and 2
(e)6 and -2
Step-by-step explanation:
(a)a negative integer
We consider the integers 5 and 8
Difference = 5-8 =-3
3 is a negative integer.
(b)Zero
We consider the integers 5 and 5
Difference = 5-5 =0
(c) an integer smaller than both the integer.
We consider the integers 7 and 5
Difference = 7-5 =2
2 is smaller than both integers.
(d) an integer smaller than only one of the integers.
We consider the integers 6 and 2
Difference =6-2=4
4 is smaller than only 6.
(e)an integer greater than both the integers
We consider the integers 6 and -2
Difference =6-(-2)=6+2=8
8 is greater than both 6 and -2.
X^2 - x - 20
(x + 4)(x - 5) <==
x^2 - x - 20.....the last sign, which is negative, tells me that one set is positive and one set is negative. The first sign, which is also negative, tells me that the larger number will be negative. Now u have to find 2 numbers, that when added equal -1 and when multiplied, equal -20....those numbers are -5 and 4. so ur answer is : (x + 4)(x - 5)
Basically you know that they are 2 consecutive numbers whose product is 1980.
<span>n*(n+1)=1980 </span>
<span>n^2 + n - 1980 = 0 </span>
<span>(n -44)(n + 45)= 0 </span>
<span>n=44 </span>
<span>so the 2 page numbers is 44 and 45. </span>
<span>The faster way is just to take the square root of 1980 and since that is 44.497 you can conclude that the 2 numbers is below and above it (44, 45)</span>
I'm assuming you are talking about polynomials.
For example, I have x^2 + 2x + 1, and I want to add 2x^2 + x + 2
Then the like terms here are:
x^2 and 2x^2, 2x and x, 1 and 2, they are quadratic, linear and constant, respectively.
