Let 
represent the depth of the miner and equipments elevator, respectively. We know that equipment elevator descends with a velocity of 
feet per second, and the miners one descends with a velocity of 
feet per second.
If we start counting time (
) when the equipment elevator begins to descend, after 
seconds its depth will be
On the other hand, the miner elevator follows the same rule, but we have to use its velocity, and remember that it starts with a delay of thirty seconds:
Now, we have to wait the 30 seconds of delay, and then another 14 seconds. This means that we want to know the positions of both elevators when 
. Let's plug this value into the two equations:
So, the equipment elevator is 176 feet deep, and the miner elevator is 210 feet deep, and thus this is the deeper one.
Step-by-step explanation:
The formula for arc length [for the angle in degrees] is:
here,
= degrees
= radius
using this we'll solve all the parts:
r = 10, n = 20:
from here, it is just simplification:
2 and 360 can be resolved: 360 divided by 2 = 180
10 and 180 can be resolved: 180 divided by 10 = 18
finally, both 20 and 18 are multiples of 2 and can be resolved:
Option (E)
r=3, n=6:
Option (D)
r=4 n=7
Option (C)
r=2 n=x
Option (D)
r=y n=x
Option (E)
Unfortunately, you haven't shared "the following points."
The equation of a circle centered at the origin and whose radius is 10 is
x^2 + y^2 = 10^2.
Step-by-step explanation:
Step 1: On the horizontal axis, we can choose the scale to be 1 unit = 11 lb.Since the weights in the table start from 65, not from 0, we give a break/kink on the X-axis. Step 2: On the vertical axis, the frequencies are varying from 4 to 10.Thus, we choose the scale to be 1 unit = 2.
Answer:
B. -4
Step-by-step explanation:
The function only has one y-value: -4. That is the entirety of its range.
