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Alona [7]
3 years ago
11

A bag contains blue and pink balls. There are 8 more blue balls than pink balls. Identify the expression that represents the pro

bability that a person will pick a blue ball first and then a pink ball without replacement. Then find the probability of someone picking a blue ball and then a pink ball if the bag originally contains 5 pink balls. Round to the nearest hundredth.
Mathematics
2 answers:
8_murik_8 [283]3 years ago
7 0
Let 
b---> the original amount of blue balls in the bag
p---> the original amount of pink balls in the bag

we know that
b=8+p
p=5
so
b=8+5----> b=13

step 1
Find the total of balls originally in the bag
total =13+5-----> 18

step 2
find <span>the probability that a person will pick a blue ball first
</span>Find P(b)
P (b)=13/18

step 3
Find the probability that a person will pick a pink ball second <span>without replacement
the total of balls now is (18-1)-------> 17
P(p)=5/17

step 4
Find </span><span>the probability that a person will pick a blue ball first and then a pink ball without replacement 
</span>(13/18)*(5/17)-----> (13*5)/(18*17)------> 65/306-----> 0.21

the answer is
0.21
notka56 [123]3 years ago
7 0

Answer:

0.212

Step-by-step explanation:

Thinking process:

Let the b  = the original blue balls in the bag

and p = the original number of pink balls in the bag

Thus,

the number of blue balls is more than pik balls, therefore:

b = 8 + p

and p = 5

therefore, b = 8 + 5

                    = 13

The total number of balls = b + p

                                           = 5 + 13

                                           = 18

Probability of person picking a blue ball, P(b) = \frac{13}{18}

The probability that a person picks a pink ball without replacement = 18 - 1

                                                                                                                 = 17

= \frac{5}{17}

The probability that a person will pick a blue ball and pick ball without replacement =

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Answer:

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x=  

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Step-by-step explanation:

8 0
3 years ago
From a box containing 10 cards numbered 1 to 10, four cards are drawn together. The probability that their sum is even is 21 21
ankoles [38]

Answer:

Step-by-step explanation:

We know that between 1 to 10 there are 5 even and 5 odd numbers.

We could get 4 even cards , 4 odd cards or 2 odd and 2 even cards

Let´s check all this combinations

Case 1: When all 4 numbers are even:  

We are going to take 4 of the 5 even numbers in the box so we have

5C4=5

Case 2: When all 4 numbers are odd:  

We are going to take 4 of the 5 odd numbers in the box, so we have

5C4=5

Case 3: When 2 are even and 2 are odd:

We are giong to take 2 from 5 even and odd cards in the box so we have

 

5C2 * 5C2

Remember that we obtain the probability from

\frac{Number-of-favourable-Outcome}{Total-number-of-outcomes}

So we have the number of favourable outcomes but we need the Total cases for drawing four cards, so we have that:  

We are taking 4 of the 10 cards:

10C_4=210

Hence we have that the probability that their sum is even

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8 0
3 years ago
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Answer:

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Step-by-step explanation:


8 0
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First, we obtain the gradient (slope) of the first parallel line

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Recall that since both lines are parallel, we have that,

m_1=m_2

Thus

m_2\text{ = 1}

Hence, we can find the equation of the parallel line given that it passes through the points (-4, -3)

Using

\begin{gathered} y\text{ = mx + c} \\ \text{where m = m}_2\text{ = 1} \\ \text{and x = -4 ,  y = -3, we have} \\ -3\text{ = 1(-4) + c} \\ -3\text{ = -4 + c} \\ 4\text{ - 3 = c} \\ c\text{ = 1} \\ \text{Thus, the equation of the line is y = (1)x + 1} \\ y\text{ = x + 1} \end{gathered}

5 0
1 year ago
On Pennsylvania's interstate highway the speed limit is 65 mph. The minimum speed is 45 mph. Write a compound inequality that re
qaws [65]

Let x be the speed.

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The minimum is 45, so x also has to be greater than or equal to 45

45 <= x => 65

6 0
3 years ago
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