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julsineya [31]
4 years ago
11

How many copies of a dominant allele of a specific trait does a child need to exhibit that trait?

Biology
2 answers:
uranmaximum [27]4 years ago
7 0

Answer:

The correct answer will be- only one copy of the dominant allele of a specific trait is enough to exhibit that trait.

Explanation:

Mendel's Law of Dominance states that dominant allele will always mask the recessive allele. Therefore, a cross between a homozygous recessive and a homozygous dominant allele will always express the dominant trait, while still having a heterozygous allele in genotype.

So, according to the law of dominance, the child with only one copy of the dominant allele will have that specific trait because the dominant allele will mask the recessive allele.

Thus, the correct answer would be one copy.

Archy [21]4 years ago
5 0
Assuming Complete Dominance, Only 1 copy of a Dominant allele of a specific trait is needed to exhibit that trait.
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In watermelons, bitter fruit (B) is dominant to sweet fruit (b), and yellow spots (S) are dominant to no spots (s). The genes fo
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If an F1 plant is backcrossed with the sweet, unspotted parent, the phenotypic proportion that is expected in the offspring will be in the ratio of 1:1:1:1.

<h3>What is Backcross?</h3>

Backcross may be defined as a type of cross where the F1 hybrid is crossed with either the recessive or dominant traits.

This question typically represents a dihybrid cross implicating two genes, one coding for fruit taste and the other for spot color. The allele for bitter taste (B) and yellow spot (S) is dominant over the allele for sweet taste (b) and no spot (s) respectively.

So, a heterozygous F1 resulting from a cross between a purebred dominant (bitter fruit, yellow spot) and purebred recessive (sweet fruit, no spot) will have a BbSs genotype.

When the F1 hybrid BbSs is backcrossed with the sweet, unspotted parent (bbss), the phenotypes with their proportions are given below:

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The Punnett square of this cross is described below:

Therefore, if an F1 plant is backcrossed with the sweet, unspotted parent, the phenotypic proportion that is expected in the offspring will be in the ratio of 1:1:1:1.

To learn more about Dihybrid cross, refer to the link:

brainly.com/question/8083392

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