In this problem, you apply principles in trigonometry. Since it is not mentioned, you will not assume that the triangle is a special triangle such as the right triangle. Hence, you cannot use Pythagorean formulas. The only equations you can use is the Law of Sines and Law of Cosines.
For finding side a, you can answer this easily by the Law of Cosines. The equation is
a2=b2 +c2 -2bccosA
a2 = 11^2 + 8^2 -2(11)(8)(cos54)
a2 = 81.55
a = √81.55
a = 9
Then, we use the Law of Sines to find angles B and C. The formula would be
a/sinA = b/sinB = c/sinC
9/sin54° = 11/sinB
B = 80.4°
9/sin54° = 8/sinC
C = 45.6°
The answer would be: a ≈ 9, C ≈ 45.6, B ≈ 80.4
Answer:
8(x) = 56 (x = 7) (x) + 5 3/4 = 8 3/4 (x = 3) x/2 = 3.5 (x = 7) Neither x - 2.56 = 0.44 (x = 3)
Step-by-step explanation:
Ok so find 20% off and see if less tha 75
percent means parts out of 100
20% means 20/100=1/5
'of' means multiply
20% of 80=1/5 times 80=16
off means subtract
disctoun tof 16 is 80-16=64
64<75
how much left over
75-spent=left over
75-64=11
anwwer is $11 left over and enough money to buy
I think its 201.333333333
Answer:
c Aerobics and jumping rope
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