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Sladkaya [172]
3 years ago
15

Solve polynomials 7/5 + 3/4 × 2 / 5-3 / 2

Mathematics
2 answers:
lapo4ka [179]3 years ago
5 0

Answer:

Step-by-step explanation:

7/5 + 3/4 x 2/5 - 3/2

 7/5 + 3/10 - 3/2

    17/10 - 3/2

         1/5

blagie [28]3 years ago
5 0

Step-by-step explanation:

<em>Here</em><em>, </em><em> </em><em>the</em><em> </em><em>given</em><em> </em><em>polynomial</em><em> </em><em>are</em><em>,</em>

<em>=</em><em>7</em><em>/</em><em>5</em><em>+</em><em>3</em><em>/</em><em>4</em><em>×</em><em>2</em><em>/</em><em>5</em><em>-3</em><em>/</em><em>2</em>

<em>multiplying</em><em> </em><em>3</em><em>/</em><em>4</em><em> </em><em>and</em><em> </em><em> </em><em>2</em><em>/</em><em>5</em>

<em>=</em><em> </em><em>7</em><em>/</em><em>5</em><em>+</em><em>6</em><em>/</em><em>2</em><em>0</em><em>-3</em><em>/</em><em>2</em>

<em>taking</em><em> </em><em>LCM</em><em> </em><em>and</em><em> </em><em>adding</em><em> </em><em>them</em><em>.</em>

<em>=</em><em>(</em><em>7</em><em>×</em><em>4</em><em>+</em><em>6</em><em>×</em><em>1</em><em>-3</em><em>×</em><em>1</em><em>0</em><em>)</em><em>/</em><em>2</em><em>0</em>

<em>by</em><em> </em><em>simplifying</em><em> </em><em>it we get</em><em>, </em><em> </em><em>the</em><em> </em><em>answer is</em><em> </em><em>1</em><em>/</em><em>5</em><em>.</em>

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em>

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The radius of a circle is 13miles. what is the area of a sector bounded by a 20 degree arc
Stolb23 [73]

Answer:

Area of the sector = 29.48 square miles.

Step-by-step explanation:

Given:

Radius of a circle = 13 miles

Angle bounded by the arc = 20 deg

To find

Area of the sector bounded by 20 degrees.

Note: Area of a sector = \frac{(\theta)}{360}\times \pi\times r^2

Plugging the values in the equation.

⇒ \frac{(\theta)}{360}\times \pi\times r^2

⇒ (\frac{20}{360})\times  3.14\times 13^2

⇒ 29.48 square-miles

So the area of the sector bounded by 20 degree arc is 29.48 square miles.

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4 years ago
Help please need those answers
icang [17]

We know: The sum of the measures of the angles of a triangle is equal 180°.

We have: m∠A =65°, m∠B =  (3x - 10)° and m∠C = (2x)°.

The equation:

65 + (3x - 10) + 2x = 180

(3x + 2x) + (65 - 10) = 180

5x + 55 = 180        <em>subtract 55 from both sides</em>

5x = 125          <em>divide both sides by 5</em>

x = 25

m∠B =  (3x - 10)° → m∠B =  (3 · 25 - 10)° = (75 - 10)° = 65°

m∠C = (2x)° → m∠C = (2 · 25)° = 50°

<h3>Answer: x = 25, m∠B = 65°, m∠C = 50°</h3>
8 0
3 years ago
Translate the phrase, then simplify. Subtract eighty-two from one hundred fifty
emmasim [6.3K]

Answer:

It is 18

Step-by-step explanation:100-82=18

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4 years ago
Find the length of line segment UV.
pshichka [43]

Answer:

The length of the line segment UV is 76 units

Step-by-step explanation:

In a triangle, the line segment joining the mid-points of two sides is parallel to the third side and equal to half its length

In Δ ONT

∵ U is the mid-point of ON

∵ V is the mid-point of TN

→ That means UV is joining the mid-points of two sides

∴ UV // OT

∴ UV = \frac{1}{2} OT

∵ UV = 7x - 8

∵ OT = 12x + 8

∴ 7x - 8 = \frac{1}{2} (12x + 8)

→ Multiply the bracket by \frac{1}{2}

∵ \frac{1}{2} (12x + 8) =  \frac{1}{2} (12x) +  \frac{1}{2} (8) = 6x + 4

∴ 7x - 8 = 6x + 4

→ Add 8 to both sides

∴ 7x - 8 + 8 = 6x + 4 + 8

∴ 7x = 6x + 12

→ Subtract 6x from both sides

∴ 7x - 6x = 6x - 6x + 12

∴ x = 12

→ Substitute the value of x in the expression of UV to find it

∵ UV = 7(12) - 8 = 84 - 8

∴ UV = 76

∴ The length of the line segment UV is 76 units

8 0
3 years ago
Colin is skateboarding and is riding a rail. The rail is attached to two poles. The first pole is 80 cm tall and the
Vinvika [58]

Answer:

\sqrt{4.49m}

Step-by-step explanation:

the unit of length is meter,

so, 80cm=0.8cm, 10cm=0.1m

the length of the rail=\sqrt{(0.8-0.1)^2+2^2}

                                  =\sqrt{4.49m}

5 0
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