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Elena L [17]
3 years ago
9

What is the probability of rolling a four then a three

Mathematics
1 answer:
spayn [35]3 years ago
6 0

Answer:

\frac{1}{36}

Step-by-step explanation:

Total possibilities when we a roll a die at a time are 6

given we should have four for first time and then three

let us assume we rolled the dice we may get 1,2,3,4,5,6(any of these) the probability to get 4 is

PROBABILITY=\frac{\textrm{FAVOURABLE CHANCES}}{\textrm{TOTAL CHANCES}}

Favourable chances=1

Total chances=6

Probability=\frac{1}{6}

the prabability to get 4 in first roll is \frac{1}{6}.

let us assume we rolled the dice for second time again we may get 1,2,3,4,5,6(any of these) the probability to get 3 is

Favourable chances=1

total chances=6

probability=\frac{1}{6}

the probability to get 3 in second roll irrespective of first one is \frac{1}{6}

the probability to get 4 in first time and then 3 is

The probability to occur both events at a time is multiplication of individual probabilities

So,

probablility to get 4 in first roll=\frac{1}{6}

probability to get 3 in second roll=\frac{1}{6}

probability to occur both at a same time is =\frac{1}{6} \times\frac{1}{6}=\frac{1}{36}

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