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mezya [45]
3 years ago
14

andrea put 2 quarts of water and 1/2 cups of lemon juice in a pitcher how many total cupsof liquid are in a pitcher

Mathematics
2 answers:
cricket20 [7]3 years ago
4 0
4 quarts is a whole so 2 quarts would be 1/2
1 cup is equal to 4 quarts but a half a cup is only 2 quarts which again is 1/2 so...
1/2+1/2=1
Alborosie3 years ago
3 0
2 quarters is 2/4 which is 1/2 so all you are doing is 1/2 + 1/2 which is just one
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Tina’s pay stub is shown at right. Find the missing numbers.
kolbaska11 [484]
Hourly Rate: $6.77
Federal Tax Income: $16.25
Other Federal Taxes: $12.43
Net Pay: $127.05
5 0
3 years ago
Pedro le dice a María si cambias los billetes de 10 € que tienes por billetes de 5 € y los billetes de 5 € por billetes de 10 €
Bad White [126]

Answer: Maria has 10 bills of 5€ and 10 bills of 10€.

She has a total of 150€.

Step-by-step explanation:

Let be "f" the number of 5€ bills that Maria has and "t" the number of 10€ bills that Maria has.

Set up a system of equations:

\left \{ {{f+t=20} \atop {5f+10t=10f+5t}} \right.

Use the Substitution method to solve the system of equations:

1. Solve for "f" from the first equation:

f=20-t

2. Substitute the equation obtained into the second equation and solve for "t".

Then:

5(20-t)+10t=10(20-t)+5t\\\\100-5t+10t=200-10t+5t\\\\20t-10t=100\\\\t=\frac{100}{10}\\\\t=10

3. Substitute the value of "t" into the equation f=20-t and evaluate:

f=20-10\\\\f=10

Therefore, Maria has 10 bills of 5€ and 10 bills of 10 €.

So the total amount of money she has, is:

Total=10(5)+10(10)=150

She has a total of 150€.

5 0
4 years ago
What is a number that can evenly be divided by 70 and 65
Tasya [4]
4,550 is the answer when you multiply the two numbers together.
4 0
4 years ago
Suppose that 70% of college women have been on a diet within the past 12 months. A sample survey interviews an SRS of 267 colleg
Fofino [41]

Answer:

The probability that 75% or more of the women in the sample have been on a diet is 0.037.

Step-by-step explanation:

Let <em>X</em> = number of college women on a diet.

The probability of a woman being on diet is, P (X) = <em>p</em> = 0.70.

The sample of women selected is, <em>n</em> = 267.

The random variable thus follows a Binomial distribution with parameters <em>n</em> = 267 and <em>p</em> = 0.70.

As the sample size is large (n > 30), according to the Central limit theorem the sampling distribution of sample proportions (\hat p) follows a Normal distribution.  

The mean of this distribution is:

\mu_{\hat p} = p = 0.70

The standard deviation of this distribution is: \sigma_{\hat p}=\sqrt{\frac{p(1-p}{n}} =\sqrt{\frac{0.70(1-0.70}{267}}=0.028

Compute the probability that 75% or more of the women in the sample have been on a diet as follows:

P(\hat p \geq 0.75)=P(\frac{\hat p-\mu_{\hat p}}{\sigma_{\hat p}} \geq \frac{0.75-0.70}{0.028}) =P(Z\geq0.179)=1-P(Z

**Use the <em>z</em>-table for the probability.

P(\hat p \geq 0.75)=1-P(Z

Thus, the probability that 75% or more of the women in the sample have been on a diet is 0.037.

7 0
3 years ago
Which of the following is the solution to the following systems of inequalities? (picture included)
Ymorist [56]

Answer:

  C.  (see the attachment)

Step-by-step explanation:

Both inequalities include the "or equal to" case, so both boundary lines will be solid. That excludes choices A and D.

The first inequality is plotted the same way in all graphs, so we must look at the second inequality. The relationship of y and the comparison symbol is ...

  -y ≥ (something)

If we multiply by -1, we get ...

  y ≤ (something else)

This means the solution space will be <em>on or below (less than or equal to) the boundary line</em>. This is the shaded area in graph C. (Graph B shows shading <em>above</em> the line.)

___

<em>Further comment</em>

Since the boundary for the second inequality is fairly steep, "above" and "below" the line can be difficult to see. Rather, you can consider the relationship of x to the comparison symbol. For the second inequality, that is ...

  x ≥ (something)

indicating the solution space is <em>on or to the right of the boundary line</em>.

3 0
3 years ago
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