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Digiron [165]
4 years ago
10

I need help....!!!!!

Mathematics
1 answer:
Vikki [24]4 years ago
8 0
C. Because the full length is 44. Now the equation is 6x-5=44. Add 5 to both sides. 6x=49. 49/6= 8.16666666666 so you round and get 8.17
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The ages of a random sample of five university professors are 39, 54, 61, 72, and 59. Using this information, find a 99% confide
kondor19780726 [428]

Answer:

99% confidence interval for the population standard deviation = (74.97 , 635.20).

Step-by-step explanation:

We are given that the ages of a random sample of five university professors are 39, 54, 61, 72 and 59. Also, it is provided that the ages of university professors are normally distributed.

So, firstly the pivotal quantity for 99% confidence interval for the population standard deviation is given by;

         P.Q. = \frac{(n-1)s^{2} }{\sigma^{2} } ~ \chi^{2} __n_-_1

where, s = sample standard deviation

            \sigma = population standard deviation

            n = sample of university professors = 5

Also, s^{2} = \frac{\sum (X-\bar X)^{2} }{n-1} = 144.5

So, 99% confidence interval for population standard deviation,\sigma is;

P(0.2070 < \chi^{2} __5_-_1 < 14.86) = 0.99 {As the table of \chi^{2} at 4 degree of freedom

                                                      gives critical values of 0.2070 & 14.86}

P(0.2070 < \frac{(n-1)s^{2} }{\sigma^{2} } < 14.86) = 0.99

P( \frac{ 0.2070}{(n-1)s^{2} } < \frac{1 }{\sigma^{2} } < \frac{ 14.86}{(n-1)s^{2} } ) = 0.99

P(\frac{ (n-1)s^{2}}{14.86 } < \sigma^{2} < \frac{ (n-1)s^{2}}{0.2070 } ) = 0.99

99% confidence interval for \sigma^{2} = ( \frac{ (n-1)s^{2}}{14.86 } , \frac{ (n-1)s^{2}}{0.2070 } )

                                                   = ( \frac{ (5-1) \times 144.5^{2}}{14.86 } , \frac{ (5-1) \times 144.5^{2}}{0.2070 } )

                                                   = (5620.525 , 403483.092)

99% confidence interval for \sigma = ( \sqrt{5620.525} , \sqrt{403483.092} )

                                                  = (74.97 , 635.20)

Therefore, 99% confidence interval for the population standard deviation of the ages of all professors at the university is (74.97 , 635.20).

8 0
4 years ago
Need help right now please
Advocard [28]

its 4

x=4

4^{2}-2x4

16-8

=8

3 0
3 years ago
Read 2 more answers
Elena drank 3 liters of water yesterday. Jada drank 3/4 times as much water as Elena. Lin drank twice as much water as Jada. A.
MaRussiya [10]

Answer:

A. Jada drank less water than Elena

B. Lin drank more water than Elena

Step-by-step explanation:

Elena drink 3 Liters of water yesterday Jada drank 3/4 times as much water as Elena. Lin drank twice as much water as Jada.

A. Did Jada drink more or less water than Elena?

B. Did Lin drink more or less water than Elena?

Elena drank 3 liters of water

Jada drank 3/4 times as much water as Elena.

Lin drank twice as much water as Jada

Elena = 3 liters

Jada = 3/4 × Elena

=3/4 × 3

=9/4 liters

=2 1/4 liters

=2.25 liters

Lin=2×Jada

=2×9/4

=18/4

=4 2/4

=4.5 liters

Did Jada drink more or less water than Elena?

A. Jada drank less water than Elena

Because 2.25 liters is less than 3 liters

B. Lin drank more water than Elena

4.5 liters is greater than 3 liters

6 0
4 years ago
(3 points) Determine whether each of these functions f : {a, b, c, d} → {a, b, c, d} is one-to-one and whether each of these fun
finlep [7]

Answer:

Step-by-step explanation:

Recall the following. Given a function f we say that  

f is one to one if for x,y in the domain of f and f(x)=f(y) then x=y.

This means that there are no different elements in the domain of the function  that are linked to the same value.

f is onto if for every y in the codomain of f, then there is an element x in the domain of f such that f(x) = y. That is, given an element y in the codomain of f, there exists and element in the domain that is linked to y.

a)  

f(a) =b, f(b)=a, f(c) = c, f(d) = d. Note that this function links each element in {a,b,c,d} to different elements in {a,b,c,d}, so it is a one to one function. Since for every element x in {a,b,c,d} there is an element y in {a,b,c,d} such that f(y) = x, then this function is also onto.  

b)  

f(a)=b, f(b) = b, f(c) = d, f(d) = c. Note that the elements a,b are linked both to b, so this function fails to be one-to-one. Also, note that the element a has no element x in {a,b,c,d} such that f(x) = a, so this function fails to be onto.  

c)  

f(a) = d, f(b) = b, f(c) = c, f(d) = d.  

As in b), since a and d are linked to d, then this function is not one to one. Also, since the element a has no element x in {a,b,c,d} such that f(x) = a, then it also fails to be onto.  

8 0
3 years ago
A piece of land is to be fenced and subdivided as shown so that each rectangle has the same dimensions. Express the total amount
posledela
13x plus 27 is the algebraic expression.
4 0
4 years ago
Read 2 more answers
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