Answer:
y = 8
Step-by-step explanation:
y= + 6
= -6
y=( x 6) + 6
y= 2+6 = 8
Find one counter example to show that the conjecture is false. angle 1 and angle 2 are supplementary, so one of the angles is a
1 answer:
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Answer:
Kindly check explanation
Step-by-step explanation:
Given the data :
Rearranged data:
5, 5, 5, 5, 6, 7, 7, 7, 8, 12, 12, 13, 13, 15, 18, 18, 27, 28, 36, 48, 52, 60, 66, 94
Start time for Suriname = 694
Mean = ΣX / n
Mean = (567 + 694) / (24 + 1) = 1261 / 25 = 50.44
B.) median start Time for initial 24 values
0.5(n+1)th term
0.5(25) = 12.5th term
(13 + 13) / 2 = 13
C.) preferred measure of center for the distribution will be the median as it shapes well in the middle of the distribution. The mean is overestimated
d) Compute the quartiles (Q1, Q2, Q3), and find the IQR for these data. Are there outliers in the time to start a business data set? If so, identify and name any outliers.
Using calculator :
Lower quartile Q1 --> 7
Median Q2 --> 13
Upper quartile Q3 --> 42
IQR = (Q3 - Q1) = 42 - 7 = 35
OUTLIER:
Lower bound : Q1 - 1.5(IQR) ; 7 - 1.5(35) = - 45.5
Upper bound : Q3 + 1.5(IQR) = 42 + 1.5(35) = 94.5
Outlier : values below - 45.5 and above 94.5
Hence, Surimanes start time is the only Outlier.
e)
Standard deviation for 24 countries :
Standard deviation = sqrt[Σ(X - mean)^2 / (N - 1)]
Usibg calculator :
Standard deviation for the 24 countries is 23.83
f)
Standard deviation
Answer:
See explanation below.
Step-by-step explanation:
Numerical way
We can calculate the mean and the standard deviation from a sample with the following formulas:
We have the following dataset for women: 34,34,26,37,42,41,35,31,41,33,30,74,33,49,38,61,21,41,26,80,72
And the mean and deviation are:
We can calculate the median ordering the data like this:
21,26,26,30,31,33,33,34,34,35,37,38,41,41,41,42,49,61,72,74,80
And the median would be on the 11 position of the data ordered, for this case is:
And the range is given by:
We can also calculate the coefficient of variation given by:
We have the following dataset for men:
43, 40,48,48,56,38,60,32,40,42,37,76,39,55,45,35,61,33,51,32,42
And the mean and deviation are:
We can calculate the median ordering the data like this:
32, 32,33,35,37,38,39,40,40,42,42,43,45,48,48,51,55,56,60,61,76
And the median would be on the 11 position of the data ordered, for this case is:
And the range is given by:
We can also calculate the coefficient of variation given by:
We se that the mean for the male groups is higher than the mean for female group. The deviation is higher for the female group comapred to the male group. We have more variation for the female group as we can see on the range and the coeffcient of variation.
Graph
We can see the histograms for each group on the figures attached.
As we can see the histogram for males is skewed to the right with the median lower than the mean.
By the other hand the histogram for the female group seems to be skewed to the right also but with missing values on the interval 50-60, for this reason we have more variation compared to the male group.
