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4 years ago

4. Solve for y: 4y - 128.(A) 32(B) 36(C) 38(D) 42

Mathematics

1 answer:

Thepotemich [5.8K]4 years ago

3 0

Answer:

A) 32

Step-by-step explanation: here you go

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Find the slope of the line through each pair of points (12,-11), (15, 12)

alexdok [17]

07713800878 it will help you in your life

3 0

3 years ago

Read 2 more answers

Mathematics can uh solve this please

guajiro [1.7K]

Answer:

$a^3 + 1 = 0$

Step-by-step explanation:

We start with the equation:

$a + \frac{1}{a} = 1$

We want to find the value of:

$a^3 + 1 =$

We can start with our previous equation and multiply both sides by a:

$(a + \frac{1}{a})*a = 1*a\\a^2 + 1 = a$

Now we can rewrite our initial expression as:

$a = 1 - \frac{1}{a}$

Replacing that in the right side, we get:

$a^2 + 1 = a = 1 - \frac{1}{a}$

Now again, let's multiply both sides by a

$a*(a^2 + 1) = a*(1 - \frac{1}{a} )\\a^3 + a = a - a/a\\a^3 + a = a - 1\\a^3 = -1\\a^3 + 1 = 0$

So we can conclude that:

$a^3 + 1 = 0$

3 0

3 years ago

Which table describes the behavior of the graph of f(x) = 2x3 – 26x – 24?

In-s [12.5K]

Answer:

For x∈ {-∞,-3} y<0, below x-axis

x∈ {-3,-1} y>0, above x-axis

x∈ {-1,4} y<0, below x-axis

x∈ {4,∞} y>0, above x-axis

Step-by-step explanation:

f(x)= $2x^{3}-26x-24$

$2x^{3}-26x-24$ =0

$2x^{3}-26x-24=0\\2x^{3}-2x-24x-24=0\\2x(x^{2} -1)-24(x+1)=0\\2x(x+1)(x-1)-24(x+1)=0\\(x+1)(2x^{2} -2x-24)=0\\=> x+1=0 => x_{1}=-1\\$

$=> 2x^{2} -2x-24=0\\=>2(x^{2} -x-12)=0\\=> x^{2} -x-12=0\\=> x^{2} -4x+3x-12=0\\=> x(x-4)+3(x-4)=0\\=> (x-4)(x+3)=0\\$

$=> x-4=0\\=> x_{2}=4\\=> x+3=0\\=>x_{3}=-3\\$

For x∈ {-∞,-3} y<0, below x-axis

x∈ {-3,-1} y>0, above x-axis

x∈ {-1,4} y<0, below x-axis

x∈ {4,∞} y>0, above x-axis

7 0

4 years ago

Read 2 more answers

Find all points on the circle (x^2) + (y^2) = 676 where the slope is 5/12

borishaifa [10]

Implicit defferentation

remember that dy/dx y= dy/dx

so
take derivitive of both sides
$2x+2y \space\ \frac{dy}{dx}=0$
solve for $\frac{dy}{dx}$
minus 2x both sides
$2y \space\ \frac{dy}{dx}=-2x$
divide both sides by 2y
$\frac{dy}{dx}=\frac{-2x}{2y}$
$\frac{dy}{dx}=\frac{-x}{y}$

when is the slope equal to $\frac{5}{12}$
solve for $\frac{dy}{dx}=\frac{5}{12}$
$\frac{dy}{dx}=\frac{5}{12}$
$\frac{5}{12}=\frac{-x}{y}$
$5y=-12x$
$y=\frac{-12}{5}x$
find where the circle and this line intersects

substitute $\frac{-12}{5}x$ for y
$x^2+(\frac{-12}{5}x)^2=676$
$x^2+\frac{144}{25}x^2=676$
$\frac{25}{25}x^2+\frac{144}{25}x^2=676$
$\frac{169}{25}x^2=676$
times both sides by $\frac{25}{169}$
$x^2=100$
sqrt both sides, take positive and negative roots
x=+/-10

sub back

$y=\frac{-12}{5}x$
$y=(\frac{-12}{5})(10) \space\ or \space\ (\frac{-12}{5})(-10)$
$y=\frac{-120}{5} \space\ or \space\ \frac{120}{5}$
$y=-24 \space\ or \space\ 24$

the points are (10,-24) and (-10,24)

8 0

3 years ago

9 cm, 5 cm and 3 cm a congruent triangle

Aleksandr [31]

Answer:

9cm x 5cm x 3cm = 135 = 67,5cm 2

2 2

Step-by-step explanation:

5 0

4 years ago

4. Solve for y: 4y - 128.(A) 32(B) 36(C) 38(D) 42​

4. Solve for y: 4y - 128.(A) 32(B) 36(C) 38(D) 42