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Afina-wow [57]
3 years ago
9

Which statement is true regarding the intervals where the function is increasing and decreasing?

Mathematics
2 answers:
dexar [7]3 years ago
8 0

Answer:

The function is increasing form (0,-\infty)

Step-by-step explanation:

Increasing function: A function is said to be increasing function

when x_1

Then,f(x_1)

Decreasing function: A function is said to be decreasing function

When x_1< x_2

Then, f(x_1)>f(x_2)

We can see that from given graph

when x goes from 0 to -infinity then

y goes from 4 to - infinity

Hence, the function is increasing on interval (0,-\infty)

When x goes from 0 to infinity

Then , y goes from 4 to -infinity.

Hence, the function is decreasing on interval (0,\infty).

KatRina [158]3 years ago
6 0

Answer:

The statement which is true regarding the intervals where the function is increasing and decreasing is:

The function is increasing in the interval (-∞,0)

Step-by-step explanation:

As we can clearly see from the graph that function is increasing in the interval (-∞,0) and decreasing in the interval (0,∞)

Hence, the statement which is true regarding the intervals where the function is increasing and decreasing is:

The function is increasing in the interval (-∞,0)

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Step-by-step explanation:

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V(t), left parenthesis, t, right parenthesis models the number of visitors in a park as a function of the outside temperature t
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Answer:

The number of visitors increases at the same rate over both intervals

Step-by-step explanation:

The unit rate at which the number of visitors in the park increases over a given temperature interval is called the average rate of change, or ARCARCA, R, C.

To find the average rate of change of a function over an interval, we need to take the total change in the function value over the interval and divide it by the length of the interval.

Hint #22 / 3

We are asked to compare the rates at which the number of visitors increases over the interval between an outside temperature of 181818 degrees Celsius and 202020 degrees Celsius, and over the interval between an outside temperature of 202020 degrees Celsius and 272727 degrees Celsius. These correspond to the domain intervals [18,20][18,20]open bracket, 18, comma, 20, close bracket and [20,27][20,27]open bracket, 20, comma, 27, close bracket.

Let's calculate the average rate of change of VVV over those intervals:

ARC_{[18,20]}ARC

[18,20]

​

A, R, C, start subscript, open bracket, 18, comma, 20, close bracket, end subscript ARC_{[20,27]}ARC

[20,27]

​

A, R, C, start subscript, open bracket, 20, comma, 27, close bracket, end subscript

\begin{aligned} \dfrac{V(20)-V(18)}{20-18}&=\dfrac{18-10}{2}\\\\&=\dfrac{8}{2}\\\\&=4\end{aligned}\quad

20−18

V(20)−V(18)

​

​

 

=

2

18−10

​

=

2

8

​

=4

​

 \begin{aligned} \dfrac{V(27)-V(20)}{27-20}&=\dfrac{46-18}{7}\\\\&=\dfrac{28}{7}\\\\&=4\end{aligned}

27−20

V(27)−V(20)

​

​

 

=

7

46−18

​

=

7

28

​

=4

​

Hint #33 / 3

The average rate of change over the interval [18,20][18,20]open bracket, 18, comma, 20, close bracket is the same as the average rate of change over the interval [20,27][20,27]open bracket, 20, comma, 27, close bracket.

Therefore, the number of visitors increases at the same rate over both intervals.

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Given: 80% people try to do this ratio and proportion  worksheet find they need some help with the problems.

Let x be the total number of people worked on this worksheet so far.

People need some help with the problems. =80% of x = 0.80x

As per given,

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Now replace the 1,2,3... with the variable representing the hour. In this case it would be h. So 5h=five dollars per hour. Because you only put the kid to bed once, you add four at the end

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