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irinina [24]
3 years ago
9

Whats the difference between 4x and x4

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
4 0
4x is substitution and x4 is to multiply.   hope that helped
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PIT_PIT [208]

Answer:

7/6

Step-by-step explanation:

\frac{ \frac{x}{4}  +  \frac{x}{3} }{ \frac{x}{2} }  = \frac{x( \frac{1}{4}  +  \frac{1}{3} )}{ x(\frac{1}{2}) } \\  =  \frac{ \frac{1}{4}  +  \frac{1}{3} }{ \frac{1}{2} }  \\  =  \frac{14}{12}  =  \frac{7}{6}

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I don’t understand this, need help.
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M+2/3=1/4m-1<br><br><br>what the formula used to find the value of m?​
zimovet [89]

<u>Answer:</u>

The value of m is \frac{-5+\sqrt{34}}{6} \text { or } \frac{-5-\sqrt{34}}{6} by using quadratic formula

<u>Solution:</u>

Given, expression is m+\frac{2}{3}=\frac{1}{4 m}-1

Now, we have to solve the above given expression.

\text { Now, } \mathrm{m}+\frac{2}{3}=\frac{1}{4 m}-1

By multiplying the equation with m, we get

\begin{array}{l}{m^{2}+\frac{2}{3} m+m=\frac{1}{4}} \\\\ {m^{2}+m\left(\frac{2}{3}+1\right)=\frac{1}{4}} \\\\ {m^{2}+\frac{5}{3} m=\frac{1}{4}}\end{array}

\begin{array}{l}{12 m^{2}+20 m=3} \\ {12 m^{2}+20 m-3=0}\end{array}

Now, let us use quadratic formula

\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here in our problem, a = 12, b = 20, c = -3

\begin{array}{l}{m=\frac{-20 \pm \sqrt{20^{2}-4 \times 12 \times(-3)}}{2 \times 12}} \\\\ {=\frac{-20 \pm \sqrt{400+144}}{24}} \\\\ {=\frac{-20 \pm \sqrt{544}}{24}} \\\\ {=\frac{-20 \pm 4 \sqrt{34}}{24}=\frac{-5 \pm \sqrt{34}}{6}} \\\\ {=\frac{-5+\sqrt{34}}{6} \text { or } \frac{-5-\sqrt{34}}{6}}\end{array}

Hence the value of m is \frac{-5+\sqrt{34}}{6} \text { or } \frac{-5-\sqrt{34}}{6} by using quadratic formula

7 0
3 years ago
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