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RUDIKE [14]
3 years ago
15

Plz, I need help as soon as possible. I have a time limit⚠️

Mathematics
1 answer:
Assoli18 [71]3 years ago
3 0

Answer:

what was your description?!?!

Step-by-step explanation:

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Find the value of x.
satela [25.4K]

Answer:

Step-by-step explanation: Find the diameter

7 0
3 years ago
Suppose we have a right triangle with legs of length a and b and hypotenuse of length c. Suppose b=3 and c=5. Then a= , For the
ANTONII [103]

Answer:

Length of right-angle  triangle 'a' = 4

b)

<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given  b = 3 and hypotenuse c = 5

Given ΔABC  is a right angle triangle

By using pythagoras theorem

        c² = a² + b²

  ⇒ a² = c² - b²

 ⇒  a² = 5²-3²

          =25 - 9

      a² = 16

⇒   a = √16 = 4

The sides of right angle triangle  a = 4 ,b = 3 and c = 5

<u><em>Step(ii):-</em></u>

<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

7 0
3 years ago
HELP ASAP ITS OVERDUE :((
drek231 [11]
A)linear because it is increasing by same amount each month
b) it's around 110 percent
6 0
4 years ago
PLEASE HELP WILL GIVE BRAINLIEST (QUESTION IN PICTURE)
anastassius [24]

Answer:

The vine is growing faster than the tree.

Step-by-step explanation:

According to the chart, the Slope-intercept form of the tree is y = 4x + 2.

The slope intercept of the vine is y = 5x + 3. Therefore, the vine is growing at a faster rate.

3 0
3 years ago
A summer biathalon-style race requires running a certain distance, and then biking a distance 2 miles more than the length of th
Vesnalui [34]

Answer:

The run is 4.875 miles long, while, the bike is 6.875 miles long.

Step-by-step explanation:

Let d = running distance and d' = biking distance.

Given that d' = d + 2 and v = running speed = 6 mph and v' = biking speed = 10 mph.

Since time, t = distance/speed, running time, t = running distance/running speed = d/6 and biking time, t' = biking distance/biking time = d'/10 = (d + 2)/10.

Since the total time, t" = 90 minutes = 1.5 hours,

t + t' = t"

So, d/6 + (d + 2)/10 = 1.5

multiplying through by the L.C.M, 30, we have

30 × d/6 + 30 ×(d + 2)/10 = 30 × 1.5

5d + 3(d + 2) = 45

expanding the brackets, we have

5d + 3d + 6 = 45

collecting like terms, we have

8d = 45 - 6

8d = 39

d = 39/8

d = 4.875 miles

d' = d + 2 = 4.875 + 2 = 6.875 miles

So, the run is 4.875 miles long, while, the bike is 6.875 miles long.

4 0
3 years ago
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