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adoni [48]
4 years ago
7

Rewrite the equation 2x+8y=16 in slope-intercept form

Mathematics
1 answer:
Shkiper50 [21]4 years ago
7 0
The goal is to solve for y. Start by subtracting 2x from both sides. This gives you 8y=-2x+16. Now just divide both sides by 8, which gives you y=-2/8x+16/8. Finally, simplify this to y=-1/4x+2.
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Find the nearest place value. Use #13 to do #14
kondaur [170]
When rounding here are the rules
If the next number to the right is 1-4, you will round down or keep the # the same.
If the next number to the right is 5-9, you will round up to the next number.

So with your # 281,421,906
a. hundred million.  This is the first 2...the number to the right of it is 8, so we will round the 2 up.  And the answer is 300,000,000
b. ten million.  This is the 8...the number to the right of it is 1, so we will round it down and 8 will remain an 8.  And the answer is 280,000,000
c. million.  This is the first 1 (281)...the number to the right is 4, so we will round down and 1 will remain a 1.  And the answer is 281,000,000
d. hundred thousand.  This is the 4...the number to the right of it is 2, so we will round down and the 4 will remain a 4.  And the answer is 281,400,000
e. thousand.  This is the second 1 (281,421)...the number to the right is the 9, so we will round up and the 1 will become a 2.  And the answer is 281,422,000

Now for #14, think about the rules.
  1. If you round it to the nearest one, you get 7.  
  2. If you round it to the nearest tenth, you get 7.0.
  3.  If you round it o the nearest hundredth, you get 7.00
  4.  It is the least number that fits the clues.

Ok basically it is saying, it rounds up to 7.  So what would be the number that would round UP to 7?  That would be 6.  I'm rounding UP because it says it is the LEAST number that fits the clues. 
3 0
4 years ago
PLZ HELP ASAP Geometry help: 2x^2 + 2y^2 - 8x +10y +2=0
Alexxx [7]
Ok so this is conic sectuion
first group x's with x's and y's with y's
then complete the squra with x's and y's


2x^2-8x+2y^2+10y+2=0
2(x^2-4x)+2(y^2+5y)+2=0
take 1/2 of linear coeficient and square
-4/2=-2, (-2)^2=4
5/2=2.5, 2.5^2=6.25
add that and negative inside

2(x^2-4x+4-4)+2(y^2+5y+6.25-6.25)+2=0
factor perfect squares
2((x-2)^2-4)+2((y+2.5)^2-6.25)+2=0
distribute
2(x-2)^2-8+2(y+2.5)^2-12.5+2=0
2(x-2)^2+2(y+2.5)^2-18.5=0
add 18.5 both sides
2(x-2)^2+2(y+2.5)^2=18.5
divide both sides by 2
(x-2)^2+(y+2.5)^2=9.25

that is a circle center (2,-2.5) with radius √9.25

6 0
3 years ago
My teacher keeps saying it’s wrong pls help, it’s question number 5
Vinvika [58]

9514 1404 393

Answer:

  A √2 is an irrational number

Step-by-step explanation:

A: √2 ≈ 1.4142135623730950488... an infinite non-repeating decimal (irrational)

B: √4 = 2 (rational)

C: ∛8 = 2 (rational)

D: √16 = 4 (rational)

3 0
3 years ago
How do you find the x and y intercepts of 5x+4y=-20
irina1246 [14]

To find the y intercept, you cover x and it's coefficient and then divide -20 by 4 to get -5. To find the x intercept, you cover y and it's coefficient and divide 5 by -20 to get -4. So, x = -4 and y= -5


8 0
3 years ago
Will mark brainliest and give 20 points! In what ways can vertical, horizontal, and oblique asymptotes be identified? Please use
spayn [35]
If both polynomials are the same degree, divide the coefficients of the highest degree terms. If the polynomial in the numerator is a lower degree than the denominator, the x-axis (y = 0) is the horizontal asymptote<span>.</span>The curves approach these asymptotes but never cross them. To find the vertical asymptote(s) of a rational function, simply set the denominator equal to 0 and solve for x.Finding Slant Asymptotes<span> of Rational Functions.

A </span>slant (oblique) asymptote occurs<span> when the polynomial in the numerator is a higher degree than the polynomial in the denominator. To </span>find the slant asymptote<span> you must divide the numerator by the denominator using either long division or synthetic division.
</span>
3 0
3 years ago
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