Point B is 6
Point A 15
And point a is greater
All u have to do is count the lines in the number
Answer:
63
Step-by-step explanation:
7x9=63
Answer:
Step-by-step explanation:
Let x represent his average walking speed.
If the average speed on the bike is 8 mph faster than his walking speed,it means that his biking speed is (x + 8) mph
Distance = speed × time
Alex returns a bike to a friends house from his own house in 1/2 hour. This means that the distance covered is
0.5(x + 8)
He walks back over the same route in 1.5 hours. This means that the distance covered is
1.5x
Since the distance covered is the same, then
1.5x = 0.5(x + 8)
1.5x = 0.5x + 4
1.5x - 0.5x = 4
x = 4 mph
Therefore, the distanceof Alex's house from his friend's house is
4 × 1.5 = 6 miles
You would do n+n+1= 575 and then you add all the n's and that's 2n + 1 = 575 them subtract 1 from 575 and then the problem would be 2n = 574 then
![\sqrt[2]{574}](https://tex.z-dn.net/?f=%20%5Csqrt%5B2%5D%7B574%7D%20)
then you'd get 287. Get it?
Given:
Height of man = 6 ft
Height of man's shadow = 11 feet
Height of building's shadow = 139 feet
To find:
The height of the building.
Solution:
We know that the heights of the objects and there shadows are always proportional.
![\dfrac{\text{Height of man}}{\text{Height of man's shadow}}=\dfrac{\text{Height of the building}}{\text{Height of building's shadow}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Ctext%7BHeight%20of%20man%7D%7D%7B%5Ctext%7BHeight%20of%20man%27s%20shadow%7D%7D%3D%5Cdfrac%7B%5Ctext%7BHeight%20of%20the%20building%7D%7D%7B%5Ctext%7BHeight%20of%20building%27s%20shadow%7D%7D)
Let x be the height of the building.
![\dfrac{6}{11}=\dfrac{x}{139}](https://tex.z-dn.net/?f=%5Cdfrac%7B6%7D%7B11%7D%3D%5Cdfrac%7Bx%7D%7B139%7D)
Multiply both sides by 139.
![\dfrac{6}{11}\times 139=x](https://tex.z-dn.net/?f=%5Cdfrac%7B6%7D%7B11%7D%5Ctimes%20139%3Dx)
![\dfrac{834}{11}=x](https://tex.z-dn.net/?f=%5Cdfrac%7B834%7D%7B11%7D%3Dx)
![75.8181...=x](https://tex.z-dn.net/?f=75.8181...%3Dx)
![x\approx 75.8](https://tex.z-dn.net/?f=x%5Capprox%2075.8)
Therefore, the building is 75.8 feet long.