4¹ = 4
4² = 16
4³ = 64
4⁴ = 256
(4⁵ = 1,024 too big)
For this case we have the following equation:
V = I * R
Where,
V: voltage
I: current
R: resistance
By clearing R we have:
R = V / I
Substituting the values:
R = (20) / (0.57)
R = 35.09 Ohms
Answer:
The resistance of the light bulb is:
R = 35.09 Ohms
Answer:
3(3a+15b)
Step-by-step explanation:
GCF: 3
Find all the prime factors between 3 and 15
3: 1,3 1*3
15: 1,3,5,15 (1*15 3*5)
3 is the GCF between the 2 numbers.
Answer:
Dominos is the better deal.
The best answer would be
2.4 x 10 ^6
10 to the sixth power multiplied by 2.4
