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ehidna [41]
3 years ago
5

How do you do this math problem? Pls, explain your work I need to get this stuff!

Mathematics
1 answer:
Debora [2.8K]3 years ago
8 0

Answer:

y = -5x-3

Step-by-step explanation:

You use rise/run to simply find the m

which will be -5/1

because look at the point at (-1,2) and now move down 5 points and 1 to the right so u will reach the point that is on the y axis. so because u moved 5 down so tht is -5 and moves 1 to the right so tht is 1 and we use rise/run to write our slope. so its -5 and now we see where our point is on the y axis so that is -3. so thats our b because b means y intercept

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Find the slope of the line through the pair of points.<br> (13, 5) and (3,5)
Ronch [10]

Answer: 0

Step-by-step explanation:

So the slope of a line is equal to rise over run, or the change in x over the change in y. We can solve for the change in x and the change in y by finding their differences. For the math, we use the formulas y2 - y1/x2 - x1. Filling in this formula we get, (5-5)/(3-13), which is equal to 0/10. Because 0 divided by anything is 0, the answer here is 0.

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3 years ago
Marc ordered a rug. He gave a deposit of 30%of the cost and will pay the rest when the rug is delivered. If the deposit was 75$,
Llana [10]

Answer:

He owes $175

Step-by-step explanation:

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x =250

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Since he already paid 75

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4 years ago
3.4 * 10 to the power of negative 2​ in standard form
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6. Find the value of x. (HINT: Find the missing angles inside the triangle first)
DIA [1.3K]

Answer:

x=120°

Step-by-step explanation:

First, let's look at ΔBAC. We can see that all three sides, AB, BC, and CA, are congruent. This means that the triangle is an equilateral triangle, meaning that all angles of the triangle are congruent.

A property of all equilateral triangles is that the interior angles are all 60°. We can prove this by dividing 180, the sum of the interior angles of a triangle, by 3, because there are three equal angles in an equilateral triangle. 180/3=60.

This means that we now know ∠BAC is 60°.

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3 years ago
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