3 years ago

HELPPP ASAPPPPPPPPPPP

Mathematics

1 answer:

makkiz [27]3 years ago

5 0

I can't see it can you retake the picture please so I can try to help if I know it?

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10(x-2) = -20<br> Solve

ale4655 [162]

Answer:

x=0

Step-by-step explanation:

10(x-2)=-20

10x-20=-20

add 20 on both sides.

10x=0

10 times 0 =0

x=0

7 0

3 years ago

Read 2 more answers

Some people advise that in very cold weather, you should keep the gas tank in your car more than half full. Irene's car had 6.

artcher [175]

Answer:

Irene spent $33.82 on gas to fill her tank.

I don’t know if im correct

7 0

3 years ago

Please help me!!!! I need this asap!

Serggg [28]

W ^10

( little 10 though like the -5 is )

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3 years ago

Is the binomial a factor of the polynomial nominal function?

Sedbober [7]

The factors for given equation f(x)= $x^{3} +3x^{2} -25x-75$ .

(x-1) - No
(x-3) - No
(x+3) - Yes
(x-5) - Yes
(x+5) - Yes

<u>Step-by-step explanation:</u>

The given equation is f(x)= $x^{3} +3x^{2} -25x-75$ .

Add 0 at the end of the equation.

$x^{3} +3x^{2} -25x-75$ = 0.

Let us group the given equation,

$(x^{3} +3x^{2}) -(25x-75)$ =0.

⇒ Group 1: $x^{3} +3x^{2}$ .

Group 2: $- 25x +75$ .

Pull out factor from each group,

⇒ Group 1: $(x+3)(x^{2})$ .

Group 2: (x+3) (-25).

Join the two group since both (x+3) is common in both groups.

$(x+3)(x^{2} -25)$ =0.

One of the factor is (x+3).

Other factors are solved by the formula, $a^{2}-b^{2} = (a+b) (a-b)$ .

$(x+3)(x^{2} -25)$ = (x+5) (x-5) .

The other factors are (x+5) and (x-5).

7 0

3 years ago

the number of cars on equally Arbor Road in here 2007 was 2500 in Year 2014 the number is 4000 calculate the percentage increase

Zepler [3.9K]

Answer:

(4000/2500)100=160%

3 0

4 years ago