Answer:
0.05
Step-by-step explanation:
There are five letters to choose from. Since there is no repetition, you can choose one of 5 for the first letter, one of four for the second letter, etc. The total number of five-letter codes is
5 * 4 * 3 * 2 * 1 = 120
Now we need to find out the number of codes that start with M and end with E.
The first position is occupied by M. There is one single letter that can be placed there. The last position is occupied by E. There is a single letter that goes there. There are 3 letters left.
1 * 3 * 2 * 1 * 1 = 6
There are 6 codes that start with M and end with E
p(code that starts with M and ends with E) = 6/120 = 0.05
<span>11,550 km has to be changed to 11,550,000 meters
G · m · t² = 4 · π² · r³ we can change that to
</span>t² = (4 · π² · r³) / <span>(G · m )
t^2 = 4*PI^2*r^3 / (G*m)
</span>t^2 = 4*PI^2*<span>(11,550,000)^3 / 6.67*10^-11*5.98*10^24kg
t^2 = </span>
<span>
<span>
<span>
6.083*10^22
</span>
</span>
</span>
<span><span>
</span>
</span>
/
<span>
<span>
<span>
3.9</span></span></span>9 * 10^14
t^2 =
<span>
<span>
<span>
152,500,000</span></span></span>
t = <span>12,350 seconds
</span>and its orbital distance it travels is 11,550 * 2*PI = 70,050 kilometers
Therefore, it is traveling at 70,050 km / 12,350 second which equals
5.67 km per second which <em>is 5,670 meters per second.</em>
Source:
http://www.1728.org/kepler3a.htm
Answer:
18
Step-by-step explanation:
6k-3 is the simplified form
Hope this helps
Standard form of a quadratic equation: ax^2 + bx + c = 0
3x - 4 = -x^2
x^2 + 3x - 4 = 0
Hope this helps!
