Answer:
Hey! The answer you're looking for is D. Uniform Resource Locator.
Answer:
class OddNumber
{
public static void main(String args[])
{
int n = 1000; //Store 1000 in Variable n typed integer
System.out.print("Odd Numbers from 1 to 1000 are:"); // Print headline of output window
for (int i = 1; i <= n; i++) //For loop to go through each number till end
{
if (i % 2 != 0) //check if number is even or odd.Not divisible by 2 without reminder means it is odd number
{
System.out.print(i + " "); //print odd numbers
}
}
}
}
Answer:
Output: 2004 2008 2058
Explanation:
In the first printf command it will print the address of the variables num, msg1, msg2. And in the second printf command it will print the values of the variables num, msg1, msg2. As the address of the structure is 2004 And the size of the integer is 4 byte so size will increase with 4 bytes and the size of character is 1 byte so it will increase by 1*50= 50 bytes.
Hence, the output is 2004 2008 2058
The answer is Status bar
Hope my answer Helps! :)
Answer:
for this, u will have to put what u already know into a few stanzas and turn it in. hope this helps.
