a boy flies a kite with 100 foot long string. the angle of elevation of the string is 48. how high is the kite from the ground.
1 answer:
With this, we should remember SOHCAHTOA (Sine: Opposite over Hypotenuse, Cosine: Adjacent over Hypotenuse, and Tangent: Opposite over Adjacent).
Using the image attached, we know that we should use Sine, because we know the hypotenuse (100 feet) and we want to know the height, or the Opposite (h).
So, we use: sin(48)=h/100 and we multiply both sides by 100 to get:
100sin(48)=h
Now, we just plug the numbers into a calculator. (Make sure your calculator is set to Degrees, or "Deg").
What we get is about 74.3144825... but we can round that to 74.3 feet.
Answer: 74.3 feet.
Using the image attached, we know that we should use Sine, because we know the hypotenuse (100 feet) and we want to know the height, or the Opposite (h).
So, we use: sin(48)=h/100 and we multiply both sides by 100 to get:
100sin(48)=h
Now, we just plug the numbers into a calculator. (Make sure your calculator is set to Degrees, or "Deg").
What we get is about 74.3144825... but we can round that to 74.3 feet.
Answer: 74.3 feet.
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Given :
Peter velocity , P = 30 mph .
Mitchell velocity , M = 40 mph .
Mitchell leaves 15 min later .
To Find :
If they drive along the same route how long will it take Mitchell to catch Peter.
Solution :
Distance covered by Peter in 15 min .
Let , time taken is x .
So , distance covered b them is equal :
Therefore , time taken by them is 45 minutes .
Hence , this is the required solution .