Question

A company had 80 employees whose salaries are summarized in the frequency distribution below. Find the standard deviation. A frequency distribution has two columns labeled from left to right "Salary (dollars)" and "Employees". The entry pairs in each row are given as follows, where the salary is listed first and the number of employees is listed second: 5001 to 10,000, 19; 10,001 to 15,000, 14; 15,001 to 20,000, 12; 20,001 to 25,000, 16; 25,001 to 30,000, 19.

Answer 1

Answer:

SD = 7588.09

Step-by-step explanation:

Check the distribution table attached to for the step by step solution:

The formula for the mean, $\bar{x} = \frac{\sum fx}{\sum f}$

$\bar {x} = \frac{1410040}{80} \\\bar {x} = 17625.5$

The variance , $V(X) = \sqrt{\frac{\sum f(x - \bar{x}^2)}{n-1} }$

$V(X) = \frac{4548750000}{80 - 1} \\V(X) = 57579113.92$

Standard Deviation,

$SD = \sqrt{V(X)} \\SD = \sqrt{57579113.92}$

SD = 7588.09

Answer 2

Answer: The standard deviation is 7540.52

Step-by-step explanation:

The working is shown in the attached photo.