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3 years ago

13

Which is greater 10,000ML or 10L of juice

1 answer:

elena-14-01-66 [18.8K]3 years ago

8 0

Neither, they are the same amount. 1,000 milliliters is equal to one liter. As such, 10000/1000 equal 10. So, 10000 mL is equal to 10 L of juice.

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Select all that apply. In order to overlook someone's faults, it takes: love an understanding that you are not perfect mental sk

zhenek [66]

In order to overlook someone's faults, it takes love and an understanding that you are not perfect.
When you love someone, you tend not to see that person's flaws, or even if you do see them, you believe those flaws are negligible. Once you understand that you yourself are not perfect (as any other human being), it will be easier for you to overlook someone else's faults.

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3 years ago

I would appreciate it if someone would show me how to solve these y-intercept tables. I’ve been confused on them for a while, an

harina [27]

Answer:

Substitute the numbers below x by x in the equation given in the middle of the table and that will be the answer for y.

Step-by-step explanation:

For example, x= -1

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3 years ago

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grandymaker [24]

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3 years ago

Read 2 more answers

The number of "destination weddings" has skyrocketed in recent years. For example, many couples are opting to have their wedding

melamori03 [73]

Answer:

We conclude that the mean wedding cost is less than $30,000 as advertised.

Step-by-step explanation:

We are given the following data set:(in thousands)

29100, 28500, 28800, 29400, 29800, 29800, 30100, 30600

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{236100}{8} = 29512.5$

Sum of squares of differences = 3408750

$S.D = \sqrt{\frac{3408750}{7}} = 697.82$

Population mean, μ = $30,000

Sample mean, $\bar{x}$ = $29512.5

Sample size, n = 8

Alpha, α = 0.05

Sample standard deviation, s = $ 697.82

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 30000\text{ dollars}\\H_A: \mu < 30000\text{ dollars}$ We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{29512.5 - 30000}{\frac{697.82}{\sqrt{8}} } = -1.975$

Now,

$t_{critical} \text{ at 0.05 level of significance, 7 degree of freedom } = -1.894$

Since,

$t_{stat} < t_{critical}$

We fail to accept the null hypothesis and reject it.

We conclude that the mean wedding cost is less than $30,000 as advertised.

8 0

3 years ago

I donot understand at all

loris [4]

Answer:

sorry i dont understand either!!!

Step-by-step explanation:

8 0

3 years ago