All categories

2 years ago

Help please find the x

Mathematics

1 answer:

kobusy [5.1K]2 years ago

4 0

Step-by-step explanation:

Two of the three interior angles are known. Both are equal to 55°. This can be seen by looking closely at the picture. To find the third angle subtract the other two from 360°

$360\textdegree-55\textdegree-55\textdegree=x$

Do the same thing only afterward subtract the third angle from 180 to find the supplementary angle

$360\textdegree-40\textdegree-28\textdegree=ans\textdegree\\180\textdegree-ans\textdegree=x$

You might be interested in

5(2f+3)=2(5f-1) Is the no solution One solution Or many solutions

Veseljchak [2.6K]

5 (2f+3)=2(5f-1)
10f+15=10f-2
10f-10f=-2-15
f=-17

7 0

3 years ago

Read 2 more answers

You have $5.85 to buy bananas to make banana bread. A banana costs $0.39. Which inequality represents the number x of bananas yo

Llana [10]

Hi!

So x represents the number of bananas we can buy. Now let's set up the inequality.

0.39x ___ 5.85

Since we can't go greater than 5.85, we can use that less than or equal to sign.

0.39x ≤ 5.85
^ the answer

Hope this helps! :)

4 0

3 years ago

Read 2 more answers

troy is going to spain and needs to convert his dollars to euros. He knows that when he goes, $5.00 is equivalent to about 3.45

astraxan [27]

Answer:

Step-by-step explanation:

3.45/5=0.69

0.69x$125=86.25

0.75x$125=93.75

93.75-86.25=$7.5

Troy would get $7.50 more than he would have if the exchange rate had stayed at .69

7 0

3 years ago

Angle Measurements 1”” degree help find out what’s the other side

Grace [21]

Answer:

80 degree

Step-by-step explanation:

missing angle + 100 degree = 180 degree (being co interior angles )

missing angle = 180 - 100

missing angle 80 degree

8 0

3 years ago

Solve the equation on the interval [0, 27r). 4(sin x)2 - 2 = 0

Ket [755]

$4[sin(x)]^2 - 2 = 0\implies 4[sin(x)]^2=2\implies [sin(x)]^2=\cfrac{2}{4}\implies [sin(x)]^2=\cfrac{1}{2} \\\\\\ sin(x)=\pm\sqrt{\cfrac{1}{2}}\implies sin^{-1}[sin(x)]=sin^{-1}\left( \pm\sqrt{\cfrac{1}{2}} \right)\implies x=sin^{-1}\left( \pm\sqrt{\cfrac{1}{2}} \right)$

$x=sin^{-1}\left( \pm\cfrac{\sqrt{1}}{\sqrt{2}} \right)\implies x=sin^{-1}\left( \pm\cfrac{1}{\sqrt{2}} \right)\implies x=sin^{-1}\left( \pm\cfrac{\sqrt{2}}{2} \right) \\\\[-0.35em] ~\dotfill\\\\ ~\hfill x=\cfrac{\pi }{4}~~,~~\cfrac{3\pi }{4}~~,~~\cfrac{5\pi }{4}~~,~~\cfrac{7\pi }{4}~\hfill$

Check the picture below.

4 0

2 years ago