Simplify.(3x^8z^2)^4

In the coordinate plane, you are given JKL with J(2, 3), K(10,4), and L(6, 10). Using the distance formula, classify JKL

Marrrta [24]

Answer:

Perimeter of JKL = 22.55 unit (Approx.)

Step-by-step explanation:

Given:

Coordinate of J = (2,3)

Coordinate of K = (10,4)

Coordinate of L = (6,10)

Find:

Perimeter of JKL

Computation:

Distance = √(x1 - x2)² + (y1 - y2)²

Distance between JK = √(2 - 10)² + (3 - 4)²

Distance between JK = √64 + 1

Distance between JK = √65

Distance between JK = 8.06 unit

Distance between KL = √(10 - 6)² + (4 - 10)²

Distance between KL = √16 + 36

Distance between KL = √52

Distance between KL = 7.21 unit

Distance between LJ = √(6 - 2)² + (10 - 3)²

Distance between LJ = √4 + 49

Distance between LJ = √53

Distance between LJ = 7.28 unit

Perimeter of JKL = Distance between JK + Distance between KL + Distance between LJ

Perimeter of JKL = 8.06 + 7.21 + 7.28

Perimeter of JKL = 22.55 unit (Approx.)

4 0

2 years ago

I started cooking at 4:55pm. I finished cooking at 6:18pm. How long did I cook?

Dafna11 [192]

Answer:

1 hour and 23 minutes

Step-by-step explanation:

4 0

3 years ago

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4x+4y=15. missing coordinate in the ordered pair (−5,?)

timama [110]

Answer:

Step-by-step explanation:

4×(-5)+4y=15 -> y= 35/4

5 0

3 years ago

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Which of these is equal to ⅔ × ¾ × ⅗?

Sphinxa [80]

Answer:

3/10

Step-by-step explanation:

Just multiply all of the numerators (top numbers) and then multiple all of the denominators (bottom numbers)

2/3x3/4x3/5 would be 18/60 Then take any number that is a factor to both 18 and 60 and divide both numbers by that factor. I could use 2 or 3 or 6 because both 18 and 60 is divisible by any of these numbers. I will choose 3. I will divide the top and bottom of 18/60 by 3 to get 6/20, now I will divide the top and bottom of that number by 2 to get 3/10

7 0

2 years ago

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30 POINTS

PtichkaEL [24]

Answer:

180 degrees per second.

Step-by-step explanation:

We have been given a graph that shows the distance covered by a tire or angular velocity of a tire with respect to the number of seconds (x).

Since we know that a tire is a circle and the measure of all the angles of a circle equals to 360 degrees.

We can see from our given graph that the tire completes one rotation in 2 seconds (2.5-0.5), so the distance covered by tire in two seconds will be 360 degrees. This means that the tire turns 360 degrees in each 2 seconds.

$\text{Degrees turned by tire in 2 seconds}=\frac{360^o}{2\text{ seconds}}$

As we are asked to find the degree change by tire per second so we will find the unit rate such that we will have 1 in our denominator. By dividing our numerator and denominator by 2 we will get,

$\text{Degrees turned by tire in every second}=\frac{180^o}{\text{ second}}$

Therefore, the tire is turning 180 degrees per second.

6 0

3 years ago

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