Answer:
x value of vertical asymptote and y value of horizontal asymptote
Step-by-step explanation:
The graph of 1/x approaches infinity as x approaches 0 (the vertical asymptote)
As x gets either bigger or smaller, 1/x approaches the x-axis (from above on the positive side, from below on the negative side) (the horizontal asymptote)
Consider 1/(x-5) + 2, at what value of x does the graph 'go nuts' ?
When the bottom of the fraction becomes 0, x - 5 becomes 0 when x = 5, so the vertical asymptote of g(x) is at x=5
What value of y does f(x) approach as x gets more positive or more negative - as x gets bigger (as an example), y approaches 0
What y value does g(x) approach as x gets bigger? Well, as x gets big, 1/(x-5) gets small, approaching 0. The smallest 0 + 2 can get is 2, so y=2 is the horizontal asymptote
1. 20 of 40 is 50% 20/40 = 1/2 1/2 = 50%
2. It is 20% because 600 is 20% of 3000
3. 40% of 30 = 12 50 = 15 10% = 3 (get it)
4, 40% of 65 = 26 50%= 32.5 (get it)
Answer:
no geniune idea
Step-by-step explanation:
Answer:
Table is attached
Step-by-step explanation:
We are given equation as

We will complete each column
First column:
we are given x=2 and we have to find y



Second column:
we are given y=3 and we have to find x



Third column:
we are given x=6 and we have to find y



Fourth column:
we are given x=0 and we have to find y



Fifth column:
we are given x=3 and we have to find y



Sixth column:
we are given y=0 and we have to find x



Seventh column:
we are given y=8 and we have to find x



now, we can complete table