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mixer [17]
3 years ago
5

0.6 + 0.008 + 0.0007 in standard form?

Mathematics
1 answer:
iren [92.7K]3 years ago
5 0

Answer:

0.0687

Explantion:

0.0007

  0.008

       0.6 +

____________

   0.0687

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Dogs are inbred for such desirable characteristics as blue eye color, but an unfortunate by-product of such inbreeding can be th
sesenic [268]

Answer:

The probability that the dogs are blue eyed and deaf is 13.02%.

Step-by-step explanation:

We are given the following information in the question:

P(Blue eyes) = 31%

P(Deaf) = 38%

P(Deaf | Blue eyes) = 42%

Formula for conditional probability:

P( A|B) = \displaystyle\frac{P(A \cap B)}{P(B)}

Now, let A be the event where the dog is deaf and B be the the event where dog is blue eyed.

P( \text{ Deaf}|\text{Blue eyes}) = \displaystyle\frac{P( \text{Deaf} \cap \text{Blue eyes})}{P(\text{Blue eyes})}\\\\0.42 = \displaystyle\frac{P( \text{Deaf} \cap \text{Blue eyes})}{0.31}\\\\P( \text{Deaf} \cap \text{Blue eyes}) = 0.42\times 0.31 = 0.1302 = 13.02\%

Hence, the probability that the dogs are blue eyed and deaf is 13.02%.

6 0
3 years ago
in terms of x, find an expression that represents the area of the shaded region. The outer square has side lengths of (x+5) and
Anna [14]

Answer:

X²-10x-10

Step-by-step explanation:

(x+5)(x-2)    Solve by factoring the polynomial

X²-10x-10    Solve and simplify

6 0
3 years ago
You have a triangular-shaped pennant hanging on your wall. The base of the pennant. Is 18 inches. The height is 1 foot. How much
EleoNora [17]

Answer:

9

Step-by-step explanation:

18 times 1

then divided by 2

is 9

6 0
4 years ago
24÷(-6)(-2)+7<br><br>^^^^^^^^^^^^
Ivahew [28]
=(-24÷6)×(-2)+7
=(-3×-2)+7
=6+7
=13
6 0
3 years ago
How would you use the Fundamental Theorem of Calculus to determine the value(s) of b if the area under the graph g(x)=4x between
-BARSIC- [3]
The Fundamental Theorem of Calculus regarding geometry states that 
\int\limits^b_a g{(x)} \, dx = F(b)-F(a)

Where F is the indefinite integral of g(x)

The first step is to integrate g(x)
\int\ {4x} \, dx = \frac{4x^{1+1} }{1+1} = \frac{4x^{2} }{2} =2 x^{2}

Then substitute the value of b and a=1 into 2x^{2}

[2 (b)^{2}]-[2 (1)^{2}] = 240
2b^{2} -2=240
2b^{2}=240+2
2b^{2}=242
b^{2}= \frac{242}{2}
b^{2}=121
b=11

Hence the limit of the area under g(x) is between a=1 and b=11

6 0
3 years ago
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