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pentagon [3]
3 years ago
9

Write a polynomial function in standard form with zeros at 1,2 and 3. HELP PLEASE!!!

Mathematics
1 answer:
dmitriy555 [2]3 years ago
6 0

Answer:

option B) f(x)=x^3-6x^2+11x-6

Step-by-step explanation:

Zeros means the point at which a given function becomes zero for the value of input.

In given case, zeros of f(x) is required at points 1,2 and 3.

Graphically the point on x-axis where the function line intersects the x-axis is the zero of the function i.e. the function value is 0,

hence

f(x)=0 when x=1

x-1=0

f(x)=(x-1)

f(x)=0 when x=2

x-2=0

f(x)=(x-2)

f(x)=0 when x=3

x-3=0

f(x)=(x-3)

Thus f(x)=(x-1)(x-2)(x-3)

Writing the above polynomial in standard form:

f(x)=x^3-6x^2+11x-6 !

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Solve the compound inequality 6b &lt; 36 or 2b + 12 &gt; 6.
Ne4ueva [31]

The solution to the compound inequality given as 6b < 36 or 2b + 12 > 6 is b < 6 or b > -3

<h3>How to solve the compound inequality?</h3>

The compound inequality is given as:

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Read more about compound inequality at

brainly.com/question/1485854


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