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pentagon [3]
3 years ago
9

Write a polynomial function in standard form with zeros at 1,2 and 3. HELP PLEASE!!!

Mathematics
1 answer:
dmitriy555 [2]2 years ago
6 0

Answer:

option B) f(x)=x^3-6x^2+11x-6

Step-by-step explanation:

Zeros means the point at which a given function becomes zero for the value of input.

In given case, zeros of f(x) is required at points 1,2 and 3.

Graphically the point on x-axis where the function line intersects the x-axis is the zero of the function i.e. the function value is 0,

hence

f(x)=0 when x=1

x-1=0

f(x)=(x-1)

f(x)=0 when x=2

x-2=0

f(x)=(x-2)

f(x)=0 when x=3

x-3=0

f(x)=(x-3)

Thus f(x)=(x-1)(x-2)(x-3)

Writing the above polynomial in standard form:

f(x)=x^3-6x^2+11x-6 !

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Answer:

A. The height of the plant after week 3 was about 2.6 inches.

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Step-by-step explanation:

The equation given:

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substituting x = 3 into the equation , we will have

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3 years ago
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The angles below are supplementary. What is the value of x? A pair of supplementary angles is shown. One angle measures 4x + 20,
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5 0
3 years ago
Read 2 more answers
If 2(a^2+b^2)=(a+b)^2 then, <br> &gt;a+b=0,<br> &gt;ab=0,<br> &gt;a=b,<br> &gt;2a=b
Tasya [4]

Answer:

2·(a^2 + b^2) = (a + b)^2

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a^2 + b^2 = 2·a·b

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(a - b)^2 = 0

a = b


7 0
3 years ago
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