All categories

2 years ago

Given the diagram below, Gitta writes that 1 + 2 + 3 = 180. Which of the following reasons allows her to write this statement

Mathematics

2 answers:

notka56 [123]2 years ago

7 0

A) Triangle sum theory. good luck!!

DaniilM [7]2 years ago

6 0

A. Triangle sum theorem

You might be interested in

The 12 members in Dante's hiking club shared 176 ounces of trail mix equally. How many ounces of trail mix did each member reciv

galina1969 [7]

Each member had to have received 14 and two thirds ounces. When you divide 176 by 12 you get 14.66666 which equals 14 and two thirds

8 0

3 years ago

Read 2 more answers

For part A and B, the options are positive and negative.

ipn [44]

Answer:

Coordinates: (2, -1)

Part A

X coordinate is positive

Y coordinate is negative

Part B

Coordinates after Y-axis reflection: (-2, -1)

X coordiate is negative

Y coordinate is negative

Good luck!

6 0

2 years ago

Read 2 more answers

What is 11.52/128 show your work

grandymaker [24]

Answer:

The answer is

Step-by-step explanation:

11.5/128

First convert the decimal to an improper fraction

That's

$11.52 = \frac{288}{25}$

So we have

$\frac{288}{25} \div 128$

Change the division sign to multiplication sign and reverse the second number

That's

$\frac{288}{25} \times \frac{1}{128}$

Simplify

$\frac{288}{3200}$

Divide through by 32

The final answer is

$\frac{9}{100}$

Hope this helps you

6 0

2 years ago

MAY I GET HELP PLEASE?

Mrac [35]

Answer:

For Part A equation: 32 + 4x = 240

8 0

2 years ago

Read 2 more answers

Find the sum of the geometric series 512+256+ . . .+4

mario62 [17]

$\bf 512~~,~~\stackrel{512\cdot \frac{1}{2}}{256}~~,~~...4$

so, as you can see above, the common ratio r = 1/2, now, what term is +4 anyway?

$\bf n^{th}\textit{ term of a geometric sequence}\\\\a_n=a_1\cdot r^{n-1}\qquad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\r=\frac{1}{2}\\a_1=512\\a_n=+4\end{cases}$

$\bf 4=512\left( \cfrac{1}{2} \right)^{n-1}\implies \cfrac{4}{512}=\left( \cfrac{1}{2} \right)^{n-1}\\\\\\\cfrac{1}{128}=\left( \cfrac{1}{2} \right)^{n-1}\implies \cfrac{1}{2^7}=\left( \cfrac{1}{2} \right)^{n-1}\implies 2^{-7}=\left( 2^{-1}\right)^{n-1}\\\\\\(2^{-1})^7=(2^{-1})^{n-1}\implies 7=n-1\implies \boxed{8=n}$

so is the 8th term, then, let's find the Sum of the first 8 terms.

$\bf \qquad \qquad \textit{sum of a finite geometric sequence}\\\\S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\r=\frac{1}{2}\\a_1=512\\n=8\end{cases}$

$\bf S_8=512\left[ \cfrac{1-\left( \frac{1}{2} \right)^8}{1-\frac{1}{2}} \right]\implies S_8=512\left(\cfrac{1-\frac{1}{256}}{\frac{1}{2}} \right)\implies S_8=512\left(\cfrac{\frac{255}{256}}{\frac{1}{2}} \right)\\\\\\S_8=512\cdot \cfrac{255}{128}\implies S_8=1020$

7 0

3 years ago