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Alenkasestr [34]
3 years ago
9

Hey everyone!!!!!!!!!!!

Mathematics
1 answer:
Ronch [10]3 years ago
8 0

Answer:

P(0, 1)

Step-by-step explanation:

Using the section formula

x_{P} = \frac{(3(-2))+(2(3))}{2+3} = \frac{-6+6}{5} = 0

y_{P} = \frac{(3(5))+(2(-5))}{2+3} = \frac{15-10}{5} = 1

Hence P(0, 1)

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