3 years ago

Hey everyone!!!!!!!!!!!

Mathematics

1 answer:

Ronch [10]3 years ago

8 0

Answer:

P(0, 1)

Step-by-step explanation:

Using the section formula

$x_{P}$ = $\frac{(3(-2))+(2(3))}{2+3}$ = $\frac{-6+6}{5}$ = 0

$y_{P}$ = $\frac{(3(5))+(2(-5))}{2+3}$ = $\frac{15-10}{5}$ = 1

Hence P(0, 1)

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