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4 years ago

11

Problem Page A line passes through the point , (6,−6) and has a slope of 32 . Write an equation in point-slope form for this lin

e.

1 answer:

Vera_Pavlovna [14]4 years ago

4 0

Y-y1=m(x-x1)
y+6=32(x-6)

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<span>The answer is 217000000000</span>

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802.06 expanded form

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Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

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Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

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$\frac{dy}{dx}=12x+14$

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$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

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Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

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Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

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3 years ago

Please Help I don't understand at all !!!!!!! I'll give 50 brainly points

kherson [118]

Answer:

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Step-by-step explanation:

To find out how many people had it initially, plug 0 in for x (implying 0 days later.)

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Answer:

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