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Pavlova-9 [17]
4 years ago
15

HELP 30 POINTS!!!!!!!!!!!!!!!!!!!!! Please explain this!!!

Mathematics
2 answers:
finlep [7]4 years ago
7 0

First, multiply the first equation by 3 to get:

3x+3y=-6

Then, add the two equations together to get

8x=16

We can follow that x=2. Plugging in x=2, we get that y=-4.

Therefore, the solution of (2,-4)

Lynna [10]4 years ago
5 0

Answer:

[2, -4]

Step-by-step explanation:

{y + x = -2

{5x - 3y = 22

-⅕[5x - 3y = 22]

{y + x = -2

{-x + ⅗y = -4⅖

_______________

1⅗y = -6⅖

____ ____

1⅗ 1⅗

y = -4 [Plug this back into both equations above to get the x-coordinate of 2]; 2 = x

I am joyous to assist you anytime.

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2) 2x + 3y= 11<br> -x-5y=-23
sergiy2304 [10]

Answer:

one solution (-2 ; 5)

Step-by-step explanation:

hello :   2x + 3y= 11 ...(*)

           -x-5y=-23.....(**)

by(**) : x= -5y+23

put this value into (*) :  2(-5y+23)+3y=11

-10y+46+3y=11

-7y = -35

y=5

but x= -5y+23

so :  x= -5(5)+23 =-2

4 0
3 years ago
(a + b)(a 2 - ab + b 2)
JulsSmile [24]

Answer:

a³ + b³

Step-by-step explanation:

Given

(a + b)(a² - ab + b²)

Each term in the second factor is multiplied by each term in the first factor, that is

a(a² - ab + b²) + b(a² - ab + b²) ← distribute both parenthesis

= a³ - a²b + ab² + a²b - ab² + b³ ← collect like terms

= a³ + b³

4 0
4 years ago
Read 2 more answers
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Answerchicken niugget john wick gun dog kidnap

Step-by-step explanation:

7 0
3 years ago
Two angles are suppplementary if their sum is 180. The larger angle measures four degrees more than seven times the measure of a
olchik [2.2K]
<span>Let the smaller angle be x
The larger angle will be 3x+8 
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4 0
4 years ago
Prove the following identity ​
Deffense [45]

Answer:

sec(x)/(tan xsin(x))=cot^2 x+1 = Ture

Step-by-step explanation:

Verify the following identity:

sec(x)/(tan(x) sin(x)) = cot(x)^2 + 1

Hint: | Eliminate the denominator on the left hand side.

Multiply both sides by sin(x) tan(x):

sec(x) = ^?sin(x) tan(x) (cot(x)^2 + 1)

Hint: | Express both sides in terms of sine and cosine.

Write cotangent as cosine/sine, secant as 1/cosine and tangent as sine/cosine:

1/cos(x) = ^?sin(x)/cos(x) sin(x) ((cos(x)/sin(x))^2 + 1)

Hint: | Simplify the right hand side.

((cos(x)/sin(x))^2 + 1) sin(x) (sin(x)/cos(x)) = (((cos(x)^2)/(sin(x)^2) + 1) sin(x)^2)/(cos(x)):

1/cos(x) = ^?(sin(x)^2 (cos(x)^2/sin(x)^2 + 1))/cos(x)

Hint: | Put the fractions in cos(x)^2/sin(x)^2 + 1 over a common denominator.

Put cos(x)^2/sin(x)^2 + 1 over the common denominator sin(x)^2: cos(x)^2/sin(x)^2 + 1 = (cos(x)^2 + sin(x)^2)/sin(x)^2:

1/cos(x) = ^?sin(x)^2/cos(x) (cos(x)^2 + sin(x)^2)/sin(x)^2

Hint: | Cancel down ((cos(x)^2 + sin(x)^2) sin(x)^2)/(sin(x)^2 cos(x)).

Cancel sin(x)^2 from the numerator and denominator. ((cos(x)^2 + sin(x)^2) sin(x)^2)/(sin(x)^2 cos(x)) = (sin(x)^2 (cos(x)^2 + sin(x)^2))/(sin(x)^2 cos(x)) = (cos(x)^2 + sin(x)^2)/cos(x):

1/cos(x) = ^?(cos(x)^2 + sin(x)^2)/cos(x)

Hint: | Eliminate the denominators on both sides.

Multiply both sides by cos(x):

1 = ^?cos(x)^2 + sin(x)^2

Hint: | Use the Pythagorean identity on cos(x)^2 + sin(x)^2.

Substitute cos(x)^2 + sin(x)^2 = 1:

1 = ^?1

Hint: | Come to a conclusion.

The left hand side and right hand side are identical:

Answer: (identity has been verified)

3 0
2 years ago
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