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4 years ago

The temperature is 21'C below zero which temperature represents this temperature +21 -21

Mathematics

1 answer:

dimulka [17.4K]4 years ago

4 0

The correct answer to this question is -21

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Last year, the world produced 3.5 billon tons of cement and that amount could increase by a billion tons by year 2050. Express t

Svetradugi [14.3K]

Answer:

$4.5 \times 10^{9}$ tons.

300 times.

Step-by-step explanation:

Last year, the world produced 3.5 billion tons of cement and that amount could increase by a billion tons by the year 2050.

So, the net production of cement by the year 2050 will be (3.5 + 1) = 4.5 billion tons i.e. $4.5 \times 10^{9}$ tons. (Answer)

Now, this amount is larger than $1.5 \times 10^{7}$ by $\frac{4.5 \times 10^{9} }{1.5 \times 10^{7}} = 300$ times. (Answer)

5 0

3 years ago

Find the smallest solution to the equation 2/3 x^2=24

klio [65]

Ok so solve
2/3 times x^2=24
m ultply both sides by 3/2 to clear fraction
x^2=36
x=-6 or 6
-6<6
answer is x=-6 is smalles solution

6 0

3 years ago

Calculate the volume of the cone. What is the volume of a cone with a height of 27 cm and a radius of 13 cm? Round your answer t

Evgen [1.6K]

Π(13)²(27/3) = 4778.4

3 0

4 years ago

Read 2 more answers

Finding Derivatives Implicity In Exercise,Find dy/dx implicity.<br> x2e - x + 2y2 - xy = 0

Klio2033 [76]

Answer:

the question is incomplete, the complete question is

"Finding Derivatives Implicity In Exercise,Find dy/dx implicity . $x^{2}e^{-x}+2y^{2}-xy$ "

Answer : $\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}$

Step-by-step explanation:

From the expression $x^{2}e^{-x}+2y^{2}-xy$ " y is define as an implicit function of x, hence we differentiate each term of the equation with respect to x.

we arrive at

$\frac{d}{dx}(x^{2}e^{-x )+\frac{d}{dx} (2y^{2})-\frac{d}{dx}xy=0\\$

for the expression $\frac{d}{dx}(x^{2}e^{-x})$ we differentiate using the product rule, also since y^2 is a function of y which itself is a function of x, we have

$(2xe^{-x}-x^{2}e^{-x})+4y\frac{dy}{dx}-x\frac{dy}{dx} -y=0\\\\(2-x)xe^{-x}+(4y-x)\frac{dy}{dx}-y=0 \\$ .

if we make dy/dx subject of formula we arrive at

$(4y-x)\frac{dy}{dx}=y-(2-x)xe^{-x}\\\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}$

5 0

4 years ago

How do I work all of these out separately

umka21 [38]

I)
7^0 = 1

ii)
5^-1 = 1/5

iii)
9^1/2 = √9 = <span>√3^2 = 3

hope that helps</span>

6 0

3 years ago