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crimeas [40]
3 years ago
12

The surface area of a regular pentagonal pyramid is 125 square yards. The base length is 5 yards. The area of the base is 37.5 s

quare yards. What is the slant height of the pyramid?
Mathematics
1 answer:
forsale [732]3 years ago
3 0

Answer:

<h2>The Slant height of the pyramid is 7 yards.</h2>

Step-by-step explanation:

The total surface area is 125 square yards.

The base area is 37.5 square yards.

Hence, the area of the curved surface is 125 - 37.5 = 87.5 square yards.

According, to the formula, the area of the curved surface is \frac{5}{2} \times bs, where b is the base length and s = slant height.

Here, it is given that b = 5 yards.

Thus, \frac{5\times5\times s}{2} = 87.5\\s = 7.

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Step-by-step explanation:

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x^2 = 19^2 - 12^2

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The point-slope form of the equation of a line that passes through points (8,4) and (0, 2) is y-
Oksi-84 [34.3K]

For this case we have that by definition, the equation of a line of the slope-intersection form is given by:

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While the point-slope equation of a line is given by:

y-y_ {0} = m (x-x_ {0})

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In this case we have a line through:

(8,4) and (0,2)

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m = \frac {2-4} {0-8} = \frac {-2} {- 8} = \frac {1} {4}

Its point-slope equation is:

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Then, we manipulate the expression to find the equation of the slope-intersection form:

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y = \frac {1} {4} x + 2

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