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crimeas [40]
3 years ago
12

The surface area of a regular pentagonal pyramid is 125 square yards. The base length is 5 yards. The area of the base is 37.5 s

quare yards. What is the slant height of the pyramid?
Mathematics
1 answer:
forsale [732]3 years ago
3 0

Answer:

<h2>The Slant height of the pyramid is 7 yards.</h2>

Step-by-step explanation:

The total surface area is 125 square yards.

The base area is 37.5 square yards.

Hence, the area of the curved surface is 125 - 37.5 = 87.5 square yards.

According, to the formula, the area of the curved surface is \frac{5}{2} \times bs, where b is the base length and s = slant height.

Here, it is given that b = 5 yards.

Thus, \frac{5\times5\times s}{2} = 87.5\\s = 7.

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2 normal types of sequences:

1. arythmetic sequences: each term is the same distance to the next term, example, 2,4,6,8, distance is 2

2. geometric sequences: the ratio of consecutive terms is the same, example: 2,4,8,16, ratio is 4:2=2:1, 2/1=2


the nth term is denoted by a_{n}
the first term is represented by a_{1}

for arythmetic sequences, the nth tem is
a_{n}=a_{1}(n-1)d where d=distance between each term

for geometric sequences the nth term is
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7 0
3 years ago
Simplify -7.39 -(-4.8)- 5.32
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simplify -7.39 -(-4.8)- 5.32 = -7.91

7 0
3 years ago
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Flip a coin 10 times and record the observed number of heads and tails. For example, with 10 flips one might get 6 heads and 4 t
zepelin [54]

Answer:

The greater the sample size the better is the estimation. A large sample leads to a more accurate result.

Step-by-step explanation:

Consider the table representing the number of heads and tails for all the number of tosses:

Number of tosses    n (HEADS)        n (TAILS)            Ratio

            10                         3                      7                    3 : 7

           30                         14                    16                   7 : 8

          100                        60                   40                  3 : 2

Compute probability of heads for the tosses as follows:

  • n = 10 tosses

        P(\text{HEADS})=\frac{3}{10}=0.30

The probability of heads in case of 10 tosses of a coin is -0.20 away from 50/50.

  • n = 30 tosses

        P(\text{HEADS})=\frac{14}{30}=0.467

The probability of heads in case of 30 tosses of a coin is -0.033 away from 50/50.

  • n = 100 tosses

        P(\text{HEADS})=\frac{60}{100}=0.60

The probability of heads in case of 100 tosses of a coin is 0.10 away from 50/50.

As it can be seen from the above explanation, that as the sample size is increasing the distance between the expected and observed proportion is decreasing.

This happens because, the greater the sample size the better is the estimation. A large sample leads to a more accurate result.

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