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3 years ago

I'm justing starting geometry honors, and I would like to know how to pass this class?! Is it easy or hard? HELP!!

Mathematics

2 answers:

rosijanka [135]3 years ago

8 0

Its different for different people but for me it was easy.

a_sh-v [17]3 years ago

5 0

I found geometry to be very easy it is a lot of fun brain teasers if u CAN do logic puzzles u will do well and enjoy it if you have a good teacher

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During a game, a basketball team scored 38 points worth of two-pointers, 33

Zigmanuir [339]

Answer:

Step-by-step explanation:

38/2 = 19

33/3 = 11

8/1 = 8

19+11+8 = 38

3 0

3 years ago

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A local flower shop sells a dozen roses for $12.85.

NNADVOKAT [17]

He owns a flower shop and sells dozens?

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3 years ago

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If 1/√a-√b=1/3 and 1/√a+√b=1/2, then find the difference of a and b.

kow [346]

<u>ANSWER:</u>

If $\frac{1}{\sqrt{a}-\sqrt{b}}=\frac{1}{3}$ and $\frac{1}{\sqrt{a}+\sqrt{b}}=\frac{1}{2}$ then the difference of a and b is 6

<u>SOLUTION:</u>

Given, $\frac{1}{\sqrt{a}-\sqrt{b}}=\frac{1}{3}$ → $\sqrt{a}-\sqrt{b}=3$ ----- (1)

And $\frac{1}{\sqrt{a}+\sqrt{b}}=\frac{1}{2}$ → $\sqrt{a}+\sqrt{b}=2$ --- (2)

We have to find difference of a and b.

Now, add (1) and (2)

$\sqrt{a}-\sqrt{b}=3$

$\sqrt{a}+\sqrt{b}=2$

Adding above two equations, we get,

$2 \sqrt{a}+0=2+3$

$\begin{array}{l}{2 \sqrt{a}=5} \\\\ {\sqrt{a}=\frac{5}{2}} \\\\ {a=\frac{25}{4}}\end{array}$

substitute $\sqrt{a}$ value in (2)

$\begin{array}{l}{\frac{5}{2}+\sqrt{b}=2} \\\\ {\sqrt{b}=\frac{2}{\sin \frac{5}{2}}} \\\\ {\sqrt{b}=\frac{4-5}{2}} \\\\ {\sqrt{b}=\frac{-1}{2}} \\\\ {b=\frac{1}{4}}\end{array}$

Now, difference of a and b is a – b = $\frac{25}{4}-\frac{1}{4}=\frac{24}{4}=6$

Hence, the difference of a and b is 6.

8 0

3 years ago

PLEASE HELP ME Determine the premiter of the figure . Use 3.14 for PI Round to the nearest tenth. Numbers are 10 in and 15in

densk [106]

Answer:

5 $\pi$ +40

Step-by-step explanation:

perimeter of circle=2 $\pi$ r

so 5 is r(radius)

so 10 $\pi$ , but since it’s semicircle, you have to divide by 2, so

5 $\pi$

perimeter of rectangle=15+10+15 because you don’t count the inside, so that equals 40

so 5 $\pi$ +40

3 0

2 years ago

The fifth graders to plant a butterfly garden. Clover grows in ½ of the garden, daisies in ¼ of the garden, coneflowers in ⅛ of

olchik [2.2K]

Answer:

Fraction of the garden used = $\frac{5}{8}$

Step-by-step explanation:

The fifth graders to plant a butterfly garden.

We are given that

Clover grows in ½ of the garden

Daisies grow in ¼ of the garden

Coneflowers grow in ⅛ of the garden

milkweed grows in ⅛ of the garden

The fifth graders notice that the butterflies land on the clover and milkweed.

We are asked to find out the fraction of the garden that the butterflies used.

Fraction of the garden used = clover + milkweed

Fraction of the garden used = $\frac{1}{2} + \frac{1}{8}$

The LCM of 2 and 8 is 8

Fraction of the garden used = $\frac{4 +1}{8}$

Fraction of the garden used = $\frac{5}{8}$

Therefore, the butterflies used $\frac{5}{8}$ fraction of the garden.

6 0

2 years ago