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3 years ago

6 mm 4 mm 2 mm 5 mm What’s the area

Mathematics

1 answer:

ruslelena [56]3 years ago

6 0

Answer:

240 mm

Step-by-step explanation:

6x4x2x5=240

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13. Imagine that you are taking a class and your chances of being asked a question in class are 1% during the first week of clas

liberstina [14]

Answer: There is probability that he will be asked a question in class during Week 7 is 64%.

Step-by-step explanation:

Since we have given that

Probability that question in class being asked during Week 1 = 1%

Probability that question in class being asked during Week 2 = 2%

Probability that question in class being asked during Week 3 = 4%

and so on.

So, we need to find the probability that question being asked in class during week 7.

Since it forms geometric series:

1%, 2%, 4%, ........

So, we need to find the 7 th term:

$a_n=ar^{n-1}\\\\a_7=ar^{7-1}\\\\a_7=1(2)^6\\\\a_7=64\%$

Hence, there is probability that he will be asked a question in class during Week 7 is 64%.

8 0

4 years ago

Geometry question please help, any help is appreciated!

Pavel [41]

$(x-x_{0})^{2} +(y-y_{0})^{2}=r^{2}
\\ \\(x+9)^{2} +(y+7)^{2} = 17^{2}
\\ \\(x+9)^{2} +(y+7)^{2} = 289$

8 0

3 years ago

Evaluate 4/49 × 7/13 give your answer as a fractions in its simplest form

Anastasy [175]

4 x 7 = 28
49 x 13 = 637
28/637
=4/91

7 0

2 years ago

The ratio of 5 rupee notes to 10 rupee notes in a purse is 3 : 4. There are 77 notes in the purse. How much money is there in th

Norma-Jean [14]

Answer:

605 rupees

Step-by-step explanation:

add the parts of the ratio 3 + 4 = 7

divide the number of notes by 7 to find one part of the ratio

$\frac{77}{7}$ = 11 ← 1 part of the ratio

3 parts = 3 × 11 = 33 ← number of 5 rupee notes

4 parts = 4 × 11 = 44 ← number of 10 rupee notes

Amount of money = (33 × 5 ) + (44 × 10) = 165 + 440 = 605 rupees

4 0

3 years ago

For the given maximization problem, (a) determine the number of slack variables needed, (b) name them, and (c) use slack var

sergij07 [2.7K]

Answer:

a) 2

b) s₁ and s₂

c) First linear equation: 5*x₁ + 8*x₂ + 10*x₃ + s₁ = 173

Second linear equation: 5*x₁ + 4*x₂ + 17*x₃ + s₂ = 254

Step-by-step explanation:

The problem statement, establishes two constraints, each one of them will need a slack variable to become a linear equation, so the answer for question

a) 2.

b) The constraints are: s₁ and s₂

c) First constraint

5*x₁ + 8*x₂ + 10*x₃ ≤ 173

We add slack variable s₁ and the inequality becomes

5*x₁ + 8*x₂ + 10*x₃ + s₁ = 173

The second constraint is:

5*x₁ + 4*x₂ + 17*x₃ ≤ 254

We add slack variable s₂ and the inequality becomes

5*x₁ + 4*x₂ + 17*x₃ + s₂ = 254

7 0

3 years ago

Read 2 more answers