Answer:
Step-by-step explanation:
1. Find two numbers that add to make the coefficient of x (in this case, -5) and that multiply to make the constant term multiplied by the coefficient of x^2 (in this case, -2 x 3 = -6)
Two numbers that work are -6 and +1
-6 x +1 = -6
-6 + -1 = -5
2. Split the middle term into the two numbers that you found.
3x^2 -6x +x -2 = 0
I've put the -6 on the left side because in our next step, when we factorise, it will be easier than having the numbers the other way around.
3. Factorise the left side by taking out common factors from each pair. The pairs I'm talking about here are '3x^2 and -6x', and 'x and -2'
3x (x-2) +1 (x-2) = 0
4. You now have two numbers both being multiplied by the term x-2. We can rearrange this equation to give us two brackets being multiplied by each other.
(3x + 1) (x-2) = 0
5. According to the Null Factor Law, if two terms are multiplied together and the result is 0, then one of those terms must be 0. Make both terms equal to 0 and solve each for x.
3x + 1 = 0 x-2 = 0
3x = -1 x = 2
x = -1/3
6. The solutions to this equation are x = 2 and x = -1/3
Answer:
109
Step-by-step explanation:
Answer:
The answer is the sum of three times a number and six, divided by the difference of seven times the number and nine
Step-by-step explanation:
3p = three x a number
7p = seven x a number
3p+6 = sum of three x a number plus six
7p-9 = difference of seven x the number minus nine
(3p+6)/(7p-9) = sum of three times x number plus six, divided by the difference of seven x the number - nine
Answer:
Any value of "x" makes the equation true
Step-by-step explanation:
(-∞,∞)
All real numbers
i hope this work for you
Answer:
oh uh ok and free points LOL
