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Sedaia [141]
3 years ago
15

2.654,2.564,2.056,2.465 from greatest to least

Mathematics
2 answers:
marusya05 [52]3 years ago
8 0
2.654, 2.564,2.465, 2.065
frozen [14]3 years ago
4 0
2.654,2.564,2.465,2.056
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Evaluate: 3(2)5. work and explanation please!
Yanka [14]
Bacically multiply 3 by 2 which is 6 then multiply that by 5 which is 30
7 0
4 years ago
What is 3x+8=-10? Can someone help me?
White raven [17]

Answer:

x=-6

Step-by-step explanation:

3x+8=-10

Isolate x and its coefficient by subtracting 8 from both sides

3x=-18

Divide by 3

x=-6

3 0
3 years ago
Read 2 more answers
If there is 45 ml of milkshake left .She used 1 part strawberry cream to 4 parts milk .How many ml of milk is left?
Debora [2.8K]

Given:

Remaining milkshake = 45 ml

She used 1 part strawberry cream to 4 parts milk.

To find:

The remaining amount of milk.

Solution:

It is given that, she used 1 part strawberry cream to 4 parts milk. It means the ratio of strawberry cream and milkshake is 1:4.

Let the remaining amount strawberry cream be x and the remaining amount of milk is 4x. Then,

x+4x=45

5x=45

x=\dfrac{45}{5}

x=9

Now, the remaining amount of milk is:

4x=4(9)

4x=36

Therefore, the remaining amount of milk is 36 ml.

3 0
3 years ago
How to find slope when giving two equations that equal each other?
9966 [12]

slope formula.:

m = (y_2 - y_1) / (x_2 - x_1)

so you just need two points from whatever function you have

Or if you already have the function formula, then just the number of the first term (if your function is this: y=ax^2 + bx + c then the a is the slope)

Hope this helps!

4 0
3 years ago
Find the general solution of the following equation: y'(t) = 3y -5
Anton [14]

Answer:

The general solution of the equation is y = \frac{A}{3}e^{3t} + 5

Step-by-step explanation:

Since the differential equation is given as y'(t) = 3y -5

The differential equation is re-written as

dy/dt = 3y - 5

separating the variables, we have

dy/(3y - 5) = dt

dy/(3y - 5) = dt

integrating both sides, we have

∫dy/(3y - 5) = ∫dt

∫3dy/[3(3y - 5)] = ∫dt

(1/3)∫3dy/(3y - 5) = ∫dt

(1/3)㏑(3y - 5) = t + C

㏑(3y - 5) = 3t + 3C

taking exponents of both sides, we have

exp[㏑(3y - 5)] = exp(3t + 3C)

3y - 5 = e^{3t}e^{3C}        

3y - 5 = Ae^{3t}                A = e^{3C}

3y = Ae^{3t} + 5    

dividing through by 3, we have

y = \frac{A}{3}e^{3t} + 5

So, the general solution of the equation is y = \frac{A}{3}e^{3t} + 5

3 0
4 years ago
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