For this case we have the following system of equations:
We can write a system of equivalent equations.
For this, it is enough to multiply one of the two equations by a scalar.
Multiplying the equation 1 by 2, we have:
Therefore, the new system of equations is:
Answer:
A system that is equivalent is:
D) 
Answer:
Step-by-step explanation:
47
Open the numbers for easy grasp by just knowing the decimal position but also you can read directly from the numbers and checking their exponents.
1.(Jurassic) 208000000
2.(Silurian) 438000000
3.(Tertiary) 66400000
4.(Triassic) 245000000
245000000Silurian, Triassic, Jurassic and Tertiary.
245000000Silurian, Triassic, Jurassic and Tertiary. And yes you are smart! Don't sell yourself short!
245000000Silurian, Triassic, Jurassic and Tertiary. And yes you are smart! Don't sell yourself short! All the best!
Answer:
5, 6, 7
Step-by-step explanation:
In order to solve for the three integers, we can assign a variable and set up an equation:
first integer: x
second integer: x + 1
third integer: x + 2
Given that 'the product of the first and third integer is 17 more than 3 times the second integer':
x(x + 2) = 3(x + 1) + 17
Distribute: x² + 2x = 3x + 3 + 17
Combine like terms: x² - x - 20 = 0
Factor: (x - 5)(x + 4) = 0
Set them equal to '0' and solve:
x - 5 = 0 x + 4 = 0
x = 5 x = -4
Since the problem asks for positive integers, x must equal 5:
first = 5
second = 5 + 1 = 6
third = 5 + 2 = 7
Answer:
Step-by-step explanation:
-32x+45-7(2x-9)=101
parenthesis first
-32x+45-14x+63=101
just combine like terms
-46x+108=101
minus 108 both sides
-46x= -7
answer is x 7 over 46
