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alexdok [17]
3 years ago
5

write an equation in slope intercept form for a line that is perpendicular to y=9x+1 and has a y intercept at -2

Mathematics
2 answers:
S_A_V [24]3 years ago
6 0
The gradient of this line is 9 so the gradient of the perpendicular line is -1/9 (the two perpendicular gradients must multiply to get -1).

The equation of a line is y=mx+c
where m is the gradient and c is the y intercept

We can then just substitute values in:

y = -1/9(x) -2
Soloha48 [4]3 years ago
4 0
Y=mx+b
m=slope
b=yint
slopes of perpendicular lines multiply to -1

y=9x+1
9 times what=-1
what=-1/9

yint=-2

too easy
slope=-1/9=m
ying=-2=b



y=-1/9x-2

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never [62]

Answer:

The answer is "0.95 and 0.5271".

Step-by-step explanation:

p (d) = 0.905 \\\\p( false\  negative)  = 0.05\\\\p(false \ positive ) = 0.10 \\\\

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In point b)  

p(\frac{d}{+ve}) = \frac{0.105 \times 0.95}{0.105 \times 0.95 +0.895 \times 0.10 }

           =\frac{0.09975}{0.09975+0.0895}\\\\=\frac{0.09975}{0.18925}\\\\= 0.5271

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3 years ago
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17 million

Step-by-step explanation:

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2 years ago
Multiply. √3 ⋅ √5 ⋅ √7 Enter your answer, in radical form, in the box.
Galina-37 [17]

Answer

<h2>\sqrt{105}</h2>

Step by step explanation

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=  \sqrt{3 \times 5 \times 7}

Calculate the product

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Hope this helps...

Best Regards!

3 0
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Answer:

Step-by-step explanation:

here you go mate

step 1

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