I need help with 1 threw7

Rihanna planned a rectangular courtyard for a park and made a scale drawing using inches as the unit of measurement. She origina

Eva8 [605]

Answer:

I think it changed from 36x to 48x

Depending on how you look at it, it could have changed from 3x to 4x or 36x to 48x.

If they said it was 18 feet instead of 18 inches, it would be 3x or 4x, but they had it as inches.

18 inches = 1.5 feet

72/1.5 = 48

54/1.5 = 36

So originally, it would have been a scale of 1 in : 36in , but it changed to 1 in : 48 in

Sorry if this was confusing.

3 0

3 years ago

Read 2 more answers

Simplify this equation please.

Sauron [17]

$\dfrac{\csc^2\theta-3\csc\theta+2}{\csc^2\theta-1}$

Identity:

$\sin^2\theta+\cos^2\theta=1\implies1+\cot^2\theta=\csc^2\theta$

So we can rewrite the denominator to get

$\dfrac{\csc^2\theta-3\csc\theta+2}{\cot^2\theta}$

Multiply numerator and denominator by $\sin^2\theta$ . Several terms will cancel since $\sin\theta\csc\theta=1$ . Also, $\cot\theta=\dfrac{\cos\theta}{\sin\theta}$ . We get

$\dfrac{1-3\sin\theta+2\sin^2\theta}{\cos^2\theta}$

Factorize the numerator, and write $\cos$ in terms of $\sin$ in the denominator to factorize it further to get

$\dfrac{(1-\sin\theta)(1-2\sin\theta)}{\cos^2\theta}=\dfrac{(1-\sin\theta)(1-2\sin\theta)}{1-\sin^2\theta}=\dfrac{(1-\sin\theta)(1-2\sin\theta)}{(1-\sin\theta)(1+\sin\theta)}$

The $1-\sin\theta$ factors cancel, leaving you with

$\dfrac{1-2\sin\theta}{1+\sin\theta}$

which you could simplify a bit further by writing

$\dfrac{1+\sin\theta-3\sin\theta}{1+\sin\theta}=1-\dfrac{3\sin\theta}{1+\sin\theta}$

3 0

4 years ago

The position of a model train, in feet along a railroad track, is given by

miv72 [106K]

Answer:

Part a) The speed is $2.5\frac{ft}{sec}$

Part b) After 4 seconds the trains is 24 ft along the track

Part c) $t=6\ sec$

Step-by-step explanation:

we have

$s(t)=2.5t+14$

This is the equation of a line in slope intercept form

where

s(t) is the position of a model train in feet

t is the time in seconds

Part a) How fast is the train moving?

The speed of the train is equal to the slope of the linear equation so

The slope m is equal to

$m=2.5\frac{ft}{sec}$

therefore

The speed is $2.5\frac{ft}{sec}$

Part b) Where is the train after 4 seconds?

For t=4 sec

substitute the value of t in the equation and solve for s

$s(4)=2.5(4)+14=24\ ft$

therefore

After 4 seconds the trains is 24 ft along the track

Part c) When will the train be 29 feet along the track?

For s(t)=29 ft

Substitute the value of s(t) in the equation and solve for t

$29=2.5t+14$

subtract 14 both sides

$29-14=2.5t$

$15=2.5t$

Divide by 2.5 both sides

$6=t$

rewrite

$t=6\ sec$

3 0

3 years ago

BRANDI WANTS TO CALCULATE THE AVERAGE SPEED

Grace [21]

Answer:

C. S = 275/3

Step-by-step explanation:

The formula for speed is S = d/t

The d is = 275

The t is = 3

So S = 275/3

Hope this helps ya!!

6 0

3 years ago

32<br> what value of x is the equation 2^2x+ 7 = 2^15true?

Talja [164]

Value of x = 7.499

Step-by-step explanation:

We need to find value of x in the equation: $2^{2x}+ 7 = 2^{15}$

This can be solved using natural log

Solving:

$2^{2x}+ 7 = 2^{15}$

Subtract 7 from both sides:

$2^{2x}+ 7-7 = 2^{15}-7$

Simplifying:

$2^{2x}=32768-7$

$2^{2x}=32761$

Using rule if f(x)=g(x) then, ln(f(x))=ln(g(x))

So,

$ln(2^{2x})=ln(32761)$

Applying log rule: logₐ(x^b)= b logₐ(x)

$2x(ln(2))=ln(32761)$

Divide both sides by 2ln(2)

$2x(ln(2))=[tex]\frac{2x(ln(2))}{2(ln(2))}=\frac{ln(32761)}{2(ln(2))} \\x=\frac{ln(32761)}{2(ln(2))}\\Rewriting\,\,32761\,\,as 181^2\\x=\frac{ln(181^2)}{2(ln(2))}\\x=\frac{2ln(181)}{2(ln(2))}\\x=\frac{ln(181)}{ln(2)}\\x=7.499$

So, Value of x = 7.499

Keywords: Solving Equations

Learn more about Solving Equations at:

#learnwithBrainly

3 0

4 years ago

I need help with 1 threw7​

I need help with 1 threw7