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aksik [14]
3 years ago
15

Simone is stranded on an island. The probability of her finding safety by waiting for help is \dfrac14 4 1 ​ start fraction, 1,

divided by, 4, end fraction. The probability of her finding safety by leaving in her raft is 0.320.320, point, 32. Which of these events is more likely?
Mathematics
2 answers:
guapka [62]3 years ago
6 0

Answer:

Simone finds safety by leaving in her raft.

P (Safety by waiting for help) = \frac{1}{4} = 0.25

P (Safety by leaving in her raft) = 0.32

0.32 > 0.25

It is more likely that Simone finds safety by leaving in her raft.

lbvjy [14]3 years ago
4 0

Answer:

Finding safety by leaving

Step-by-step explanation:

This was really difficult to read so I'm going to assume that you are supposed to compare 1/4 and .320.

1/4 = .25 < .320

The event with the larger fraction or decimal is more likely.

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Answer:

cosec²x is the answer

Step-by-step explanation:

\frac{1+tan^2x}{tan^2x} \\\\\frac{sec^2x}{tan^2x} \\\\\frac{\frac{1}{cos^2x} }{\frac{sin^2x}{cos^2x} }\\\\\frac{1}{sin^2x}\\\\cosec^2x

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3 years ago
Help me:-
Vesnalui [34]

Answer:

20 + 4y

Step-by-step explanation:

The 4 multiplies the 5 and the y, i.e., it distributes over the terms of the expression in ( ).

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2 years ago
3/4•3/4???? I can’t do it in my head and I don’t know how to make a decimal into a fraction
Monica [59]

Answer:

0.5625

Step-by-step explanation:

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0.75×0.75=0.5625

4 0
3 years ago
Read 2 more answers
“An architect is planning to incorporate several stone spheres of different sizes into the landscaping of a public park, and wor
Artist 52 [7]

Answer:

Part 1) The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Part 2) The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

Step-by-step explanation:

Step 1

Find the radius of each sphere

we know that

The circumference of a circle is equal to

C=2\pi r

<u><em>Find the radius of the sphere with a 5.50-meter circumference</em></u>

For C=5.50\ m

assume

\pi =3.14

substitute and solve for r

5.50=2(3.14)r

r=5.50/[2(3.14)]=0.88\ m

<u><em>Find the radius of the sphere with a 7.85-meter circumference</em></u>

For C=7.85\ m

assume

\pi =3.14

substitute and solve for r

7.85=2(3.14)r

r=7.85/[2(3.14)]=1.25\ m

step 2

Find the surface area of each sphere

The surface area of sphere is equal to

SA=4\pi r^{2}

<u><em>Find the surface area of sphere with a 5.50-meter circumference</em></u>

For r=0.88\ m

assume

\pi =3.14

substitute

SA=4(3.14)(0.88)^{2}

SA=9.73\ m^{2}

<u><em>Find the surface area of sphere with a 7.85-meter circumference</em></u>

For r=1.25\ m

assume

\pi =3.14

substitute

SA=4(3.14)(1.25)^{2}

SA=19.63\ m^{2}

step 3

Find the cost of finishing each sphere

we know that

To find out the cost , multiply the surface area by $92 per square meter

<u><em>Find the cost of sphere with a 5.50-meter circumference</em></u>

9.73*(92)=\$895.16

therefore

The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

<u><em>Find the cost of sphere with a 7.85-meter circumference</em></u>

19.63*(92)=\$1,805.96

therefore

The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

6 0
3 years ago
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