X^2 = 7^2 - 3^2
x = root40
If the parabola has y = -4 at both x = 2 and x = 3, then since a parabola is symmetric, its axis of symmetry must be between x = 2 and x = 3, or at x = 5/2. Our general equation can then be:
y = a(x - 5/2)^2 + k
Substitute (1, -2): -2 = a(-3/2)^2 + k
-2 = 9a/4 + k
Substitute (2, -4): -4 = a(-1/2)^2 + k
-4 = a/4 + k
Subtracting: 2 = 2a, so a = 1. Substituting back gives k = -17/4.
So the equation is y = (x - 5/2)^2 - 17/4
Expanding: y = x^2 - 5x + 25/4 - 17/4
y = x^2 - 5x + 2 (This is the standard form.)
Find real values of the number a for which a.i is a solution of the polynomial equation. ...
u,v and w are the three roots of the equation z3 - 1 = 0 . ...
Calculate all solutions of |z-1|.|z-1|=1. ...
The equation z3 - (n + i) z + m + 2 i = 0. ...
Let z' the conjugate complex number of z.
Answer:
n=-6
Step-by-step explanation:
2(n+5)=-2
distribute
2(n+5)
2xn 2x5
2n+10
2n+10=-2
subtract 10 from both sides
10-10=0
-2-10=-12
2n=-12
divide each side by 2
2n/2=n
-12/2=-6
n=-6
