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nadezda [96]
3 years ago
13

Find the solutions to the equation below. check all that apply

Mathematics
1 answer:
BartSMP [9]3 years ago
6 0

Answer:

A and E

Step-by-step explanation:

Given

20x² - 26x + 8 = 0 ( divide through by 2 )

10x² - 13x + 4 = 0

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 10 × 4 = 40 and sum = - 13

The factors are - 5 and - 8

Use these factors to split the x- term

10x² - 5x - 8x + 4 = 0 ( factor the first/second and third/fourth terms )

5x(2x - 1) - 4(2x - 1) = 0 ← factor out (2x - 1) from each term

(2x - 1)(5x - 4) = 0

Equate each factor to zero and solve for x

2x - 1 = 0 ⇒ 2x = 1 ⇒ x = \frac{1}{2} → E

5x - 4 = 0 ⇒ 5x = 4 ⇒ x = \frac{4}{5} → A

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RUDIKE [14]

Answer: 2(−5x^2 +9)(5x^2 +9)

Step-by-step explanation:

Given: 162-50x^4

Factor out 2:  2(81-25x^4)

Rewrite:  2(9^2-(5x^2)^2)

Use difference of squares:  2(9-5x^2)(9+5x^2)

Reorder (if you need to) 2(-5x^2+9)(5x^2+9)

3 0
3 years ago
Read 2 more answers
I don't understand how to do this?<br> Let f(x) = x2 − 2x + 2 and g(x) = x − 3. Find f(x) ⋅ g(x
serg [7]
Multiply the functions
(x^2-2x+2)(x-3)=
(x^2-2x+2)(x)+(-3)(x^2-2x+2)=
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x^3-2x^2+2x-3x^2+6x-6=
x^3-2x-3x^2+2x+6x-6=
x^3-5x^2+8x-6

f(x)g(x)=x^3-5x^2+8x-6

4 0
3 years ago
in this situation negative $55 represents a debit of blank on Thursday mom had a debit of blank than $55
LiRa [457]
She had $110 more than -55 hope this helps
5 0
4 years ago
I need help with this math problem
Troyanec [42]

The exact answer is 12 root 2, but you can also say approximately 17.

I got this by finding the square root of 369, and then 81. After finding these values, you get the equation...

a^2 + 9^2 = 369

a^2 + 81 = 369

a^2 = 288

And then I just found the square root of 288

3 0
4 years ago
How is adding positive and negative fractions similar to adding intergers ?
Paha777 [63]

Answer:

When you are adding or subtracting a negative fraction, you usually want to consider the numerator as negative. The method is just the same, except now you may need to add negative or positive numerators. Example 1: ... To add the fractions with unlike denominators, rename the fractions with a common denominator.

Step-by-step explanation:

<em>I GOT YOU!!!!</em>

6 0
3 years ago
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